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boyakko [2]
3 years ago
11

What is the distance between point (-5,-6) and (-3,-8)

Mathematics
2 answers:
lys-0071 [83]3 years ago
8 0

Answer:

3.

Step-by-step explanation:

Radda [10]3 years ago
5 0

Answer:

\sqrt{8} \\

Step-by-step explanation:

First, find the distance between the x values.  From -5 to -3, the distance is 2 units.  Then find the distance between the y values. From -6 to -8 the distance is 2.   Then, use the Pythagorean Theorem to find the distance.

(a^2)+(b^2)=c^2  Where a and b are the distances between the x and y values.

C will be your answer.

(2^2)+(2^2)=c^2.

4+4=c^2

8=c^2

So the answer is the square root of 8.

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70:100 in whole form
taurus [48]
The Answer Would Be 70
6 0
3 years ago
Read 2 more answers
NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.
Oliga [24]

Answer:

\displaystyle 1)48.2    \:  \: \text{sec}

\rm \displaystyle  2)3021.6 \: m

Step-by-step explanation:

<h3>Question-1:</h3>

so when <u>flash down</u><u> </u>occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,

to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

\displaystyle  - 4.9 {t}^{2}  + 229t + 346 = 0

to solve the equation can consider the quadratic formula given by

\displaystyle x =  \frac{ - b \pm  \sqrt{ {b}^{2} - 4 ac} }{2a}

so let our a,b and c be -4.9,229 and 346 Thus substitute:

\rm\displaystyle t =  \frac{ - (229) \pm  \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}

remove parentheses:

\rm\displaystyle t =  \frac{ - 229 \pm  \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}

simplify square:

\rm\displaystyle t =  \frac{ - 229 \pm  \sqrt{ 52441- 4( - 4.9)(346)} }{2.( - 4.9)}

simplify multiplication:

\rm\displaystyle t =  \frac{ - 229 \pm  \sqrt{ 52441- 6781.6} }{ - 9.8}

simplify Substraction:

\rm\displaystyle t =  \frac{ - 229 \pm  \sqrt{ 45659.4} }{ - 9.8}

by simplifying we acquire:

\displaystyle t = 48.2  \:  \:  \: \text{and} \quad  - 1.5

since time can't be negative

\displaystyle t = 48.2

hence,

at <u>4</u><u>8</u><u>.</u><u>2</u><u> </u>seconds splashdown occurs

<h3>Question-2:</h3>

to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

\displaystyle x _{  \text{max}} =  \frac{ - b}{2a}

let a and b be -4.9 and 229 respectively thus substitute:

\displaystyle t _{  \text{max}} =  \frac{ - 229}{2( - 4.9)}

simplify which yields:

\displaystyle t _{  \text{max}} =  23.4

now plug in the maximum t to the function:

\rm \displaystyle  h(23.4)- 4.9 {(23.4)}^{2}  + 229(23.4)+ 346

simplify:

\rm \displaystyle  h(23.4)  =  3021.6

hence,

about <u>3</u><u>0</u><u>2</u><u>1</u><u>.</u><u>6</u><u> </u>meters high above sea-level the rocket gets at its peak?

5 0
2 years ago
Please help me with this question. I will mark you brainliest. ​
solong [7]

<u>Answer:</u>

<em>Option D : $153</em>

<u>This is how I got that:</u>

9:30 AM to 1:15 PM = 3 hours and 45 minutes

The first hour charges $15 and for the remaining 2 hours and 45 minutes

Mr. Anand is charged 36$. Remember it says that each additional hour <em>or part thereof, </em>so the 2 hours and 45 minutes is considered 3 hours.

So our total for one paddle boat is <u>$51 </u>

<u />

But Mr. Anand hired <em>three</em> boats so we simply times 51 by 3 and get our solution to the problem:

<u>Mr. Anand must pay $153 or Option D</u>

<u></u>

<em>~That's All Folks~</em>

<em>-Siascon</em>

4 0
3 years ago
can you help me evaluate this: 7m + 14m - 6n - 5n + 2m. why do you add 6n with 5n instead of subtract?
Mademuasel [1]

Step-by-step explanation:

The reason is because it is not just 6 it is - 6 so when there are two negative numbers they don't subtract they add if it was 6n then it was to be subtracted

21m - 11n + 2m

23m - 11n

6 0
3 years ago
Shop only had 2 types of stamps left using
saveliy_v [14]

Answer:

  {3¢, 28¢} or {4¢, 19¢} or {7¢, 10¢}

Step-by-step explanation:

54 = 1×54 = 2×27 = 3×18 = 6×9

Possible values of the stamps are 1 more than the values of a pair of factors. Of course, a 2¢ and 55¢ stamp will not permit paying 54¢ in postage, so that combination won't work. However, other pairs that will work are ...

  • 3¢ and 28¢
  • 4¢ and 19¢
  • 7¢ and 10¢

7 0
3 years ago
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