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AleksandrR [38]

3 years ago

5

Estimate the solution of the system of equations

2 answers:

storchak [24]3 years ago

8 0

Answer:

I solved by substitution...

Step-by-step explanation:

DochEvi [55]3 years ago

5 0

Answer:

Around (1.5,-4) because the two lines intersect around there

Step-by-step explanation:

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james recently installed a new pool in his backyard the pool is 20 ft long 15 feet wide and 5 ft deep, what is the volume

mixer [17]

20 x 15 x 5 = 1500 ft³

8 0

3 years ago

Transform the given quadratic function into vertex form f(x) = quadratic function into vertex form f(x) = quadratic function int

vesna_86 [32]

Answer:

$f(x) = 3(x -\frac{2}{3})^2 -\frac{22}{3}$

The vertex is $(\frac{2}{3}, -\frac{22}{3})$

Step-by-step explanation:

For a general quadratic function the form is:

$ax ^ 2 + bx + c$

For the function

$f(x) = 3x ^ 2 -4x -6$

Take common factor 3.

$f(x) = 3(x ^ 2 -\frac{4}{3}x - 2)$

The values of the coefficients for the function within the parenthesis are the following: $a = 1$ , $b = -\frac{4}{3}$ , $c = -2$

Take the value of b and divide it by 2. Then, the result obtained squares it.

$\frac{b}{2}= -\frac{2}{3}$

$(\frac{b}{2})^2=\frac{4}{9}$

Add and subtract $\frac{4}{9}$

$f(x) = 3([x ^ 2 -\frac{4}{3}x +\frac{4}{9}]- 2-\frac{4}{9})$

Write the expression of the form

$f(x) = (x-\frac{b}{2})^2 +k$

$f(x) = 3(x -\frac{2}{3})^2 -\frac{22}{3}$

The vertex is $(\frac{2}{3}, -\frac{22}{3})$

3 0

3 years ago

Find the range of the data.<br> 4.8,5.5, 4.2, 8.9, 3.4, 7.5, 1.6,3.8

fredd [130]

don't know bro sorry for points comment below to talk

3 0

2 years ago

Read 2 more answers

Let A be a 3 by 6 , B be a 6 by 7 and C be a 7 by 3 matrix. Determine the size of the following matrices (if they do not exist,

kozerog [31]

Answer:

a. AB: 3 by 7

b. BA: N by N

c. A^TB: N by N

d. BC: 6 by 3

Step-by-step explanation:

Given

$A =3\ by\ 6$

$B =6\ by\ 7$

$C =7\ by\ 3$

Required

The dimension of the following matrices

As a general rule:

For A * B to be successful, the columns in a must equal the rows in B

Using this rule, we have:

$A_{m*n} * B_{n * p} = AB_{m*p}$

So:

$(a)\ AB$

$A_{3*6} * B_{6*7} \to AB_{3 * 7}$

$(b)\ BA$

$B_{6*7} * A_{3*6} \to AB_{N * N}$

The column numbers of B does not equal the row numbers of A.

Hence, BA does not exist

$(c)\ A^TB$

$A^T$ implies that:

If $A =3\ by\ 6$ , then

$A^T = 6\ by\ 3$

So:

$A^T_{6*3} * B_{6,7} \to A^TB_{N*N}$

The column numbers of A^T does not equal the row numbers of B.

Hence, $A^TB$ does not exist

$(d)\ BC$

$B_{6*7} * C_{7*3} \to BC_{6,3}$

6 0

3 years ago

Simplify your answer completely. -2 4/6 / -2/3

skad [1K]

Your answer is 2. Hope this helps!

4 0

3 years ago

Read 2 more answers