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lara [203]
3 years ago
8

What is (8n^2-26n+20) divided by (n-2)?

Mathematics
1 answer:
Mama L [17]3 years ago
7 0

Answer:

A. 8n-10

Step-by-step explanation:

8n2−26n+20/n−2

=2(4n−5)(n−2)/n−2

=8n−10


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I need help on this can you help me
miskamm [114]
Phil had 2 quarters, 1 dime and 3 pennies = 63 cents
Paul had 2 nickles = 10 cents

Total 63 + 10 = 73 cents

If Paul had 1 cent more than Phil, then Paul would have 37 cents and Phil would have 36 cents
but Paul had 10 cents 
10 cents + 27 cents = 37 cents

so 
1 quarter and 2 pennies Phil gave to Paul, total 27 cents

Answer

Phi gave Paul 1 quarter and 2 pennies.
3 0
3 years ago
Evaluate f(x)=7x+7 when x=-9
stealth61 [152]

Answer:

-56

Step-by-step explanation:

f(x) = 7x + 7

x = -9

We meed to plug in x = -9 into the first equation:

f(-9) = 7(-9) + 7

We can open up the parentheses:

f(-9) = -63 + 7

And then simplify:

f(-9) = -56

7 0
3 years ago
Two ratios that are equivalent to 5/7
grigory [225]

You could pick just about anything 3/8 is not the same thing as 5/7 and neither is 3/4

Something that is equivalent would be something like 10/14 or 20/28

3 0
3 years ago
Find the surface area of the regular pyramid shown to the nearest whole number. plz help
Sav [38]
The surface area of the regular hexagonal pyramid is
SA = (1/2) pl + B
where p is the perimeter of the base, l is the slant height of the pyramid, and B is the area of the base
The area of a regular hexagon is 3 sh
where s is the length of the side and h is the length of the apothem.
So,
SA = (1/2)(6)(12) (11) + 3(12)(6sqrt3)
SA = 770 square meters
5 0
2 years ago
Read 2 more answers
9 inches of ribbon are needed for wrapping each present. How many presents can be wrapped with 6 yards of ribbon?
netineya [11]

Answer:

a total of 24 presents can be wrapped

Step-by-step explanation:

6 x 3 = 18 feet of ribbon

18 x 12 = 216 inches of ribbon

216/9 = 24 presents can be wrapped

3 0
3 years ago
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