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egoroff_w [7]
4 years ago
11

What three things dose the speed of sound depend

Physics
1 answer:
Tcecarenko [31]4 years ago
7 0
Three factors can have an effect, it varies due to atmospheric conditions^^~

Distance

Humidity (not so much of an impact though)

Temperature

Density for an object

Hope it helps and Good luck!

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System A has masses m and m separated by a distance r; system B has masses m and 2m separated by a distance 2r; system C has mas
Anna [14]

Answer:

System D --> System C --> System A --> System B

Explanation:

The gravitational force between two masses m1, m2 separated by a distance r is given by:

F=G \frac{m_1 m_2}{r^2}

where G is the gravitational constant. Let's apply this formula to each case now to calculate the relative force for each system:

System A has masses m and m separated by a distance r:

F=G\frac{m \cdot m}{r^2}=G \frac{m^2}{r^2}

system B has masses m and 2m separated by a distance 2r:

F=G\frac{m \cdot 2m}{(2r)^2}=G \frac{2m^2}{4r^2}=\frac{1}{2} G \frac{m^2}{r^2}

system C has masses 2m and 3m separated by a distance 2r:

F=G\frac{2m \cdot 3m}{(2r)^2}=G \frac{6m^2}{4r^2}=\frac{3}{2} G \frac{m^2}{r^2}

system D has masses 4m and 5m separated by a distance 3r:

F=G\frac{4m \cdot 5m}{(3r)^2}=G \frac{20m^2}{9r^2}=\frac{20}{9} G \frac{m^2}{r^2}

Now, by looking at the 4 different forces, we can rank them from the greatest to the smallest force, and we find:

System D --> System C --> System A --> System B

5 0
4 years ago
I need help with question 8 .
Vesnalui [34]

The bike is maintaining "constant velocity".  He's moving at 15 m/s when we see him for the first time, 15 m/s later that day, and 15 m/s next week.

The car starts from zero, and goes 4.0 m/s FASTER each second. After one second, it's going 4.0 m/s. After 2 seconds, it's going 8 m/s. And after 3 seconds, it's going 12 m/s.  

This is the point at which the question wants us to compare them ... 3 seconds.  The bike is moving at 15 m/s and the car has sped up to 12 m/s. <em>The bike is moving faster than the car.</em>

If we hung around and kept watching for another second, the car would then be moving at 16 m/s, and would be moving faster than the bike.  But we lost interest after answering the question, and we left at 3 seconds.

5 0
3 years ago
What is word meaning "heated to a glow"?
adell [148]

I think the word you want is "incandescent".


5 0
3 years ago
A planet is orbiting a nearby star. Suppose that the star’s gravity increases over time. What effect will this increase most lik
zhenek [66]
The planet would stay in the same orbit but start revolving faster.
(Its year would get shorter.)
7 0
4 years ago
You are riding on a roller coaster that starts from rest at a height of 25.0 m and moves down a frictionless track to a height o
irina [24]

Answer: 20.765 m/s

Explanation:

This problem can be solved by the conservation of energy principle, this means the initial energy E_{o} must be equal to the final energy  E_{f}:

E_{o}=E_{f} (1)

Where each energy is the sum of kinetic energy K and potential energy U:

K_{o}+U_{o}=K_{f}+U_{f} (2)

Where:

K_{o}=\frac{1}{2}mV_{o}^{2}

Being m your mass and V_{o}=0 m/s your initial velocity, since the roller coaster sterted from rest.

U_{o}=mgh_{o}

Being  g=9.8 m/s^{2} the acceleration due gravity and  h_{o}=25 m your initial height

K_{f}=\frac{1}{2}mV_{f}^{2}

Being V_{f} your final velocity

U_{f}=mgh_{f}

Being h_{f}=3 m your final height

Rewritting (2):

\frac{1}{2}mV_{o}^{2}+mgh_{o}=\frac{1}{2}mV_{f}^{2}+mgh_{f} (3)

mgh_{o}=m(\frac{1}{2}V_{f}^{2}+gh_{f}) (4)

Isolating V_{f}:

V_{f}=\sqrt{2g(h_{o}-h_{f})} (5)

V_{f}=\sqrt{2(9.8 m/s^{2})(25 m-3 m)} (6)

Finally:

V_{f}=20.765 m/s This is your spedd when you arrive at 3 m height

7 0
4 years ago
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