Answer:
Charge, ![q=7.68\times 10^{-12}\ C](https://tex.z-dn.net/?f=q%3D7.68%5Ctimes%2010%5E%7B-12%7D%5C%20C)
Explanation:
It is given that,
The number of electron in a RBCs, ![n=4.8\times 10^7](https://tex.z-dn.net/?f=n%3D4.8%5Ctimes%2010%5E7)
We need to find the total charge of these electrons in the red blood cell. Let it is q. Using the quantization of charge as follows :
q = ne
e is the change on electron
![q=4.8\times 10^7\times 1.6\times 10^{-19}\\\\q=7.68\times 10^{-12}\ C](https://tex.z-dn.net/?f=q%3D4.8%5Ctimes%2010%5E7%5Ctimes%201.6%5Ctimes%2010%5E%7B-19%7D%5C%5C%5C%5Cq%3D7.68%5Ctimes%2010%5E%7B-12%7D%5C%20C)
So, the net charge is
.
<span>The answer would be, C. The reactions go to completion</span>
<span>perpendicular to the direction of wave motion </span>