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Ad libitum [116K]
3 years ago
10

I need help with question 8 .

Physics
1 answer:
Vesnalui [34]3 years ago
5 0

The bike is maintaining "constant velocity".  He's moving at 15 m/s when we see him for the first time, 15 m/s later that day, and 15 m/s next week.

The car starts from zero, and goes 4.0 m/s FASTER each second. After one second, it's going 4.0 m/s. After 2 seconds, it's going 8 m/s. And after 3 seconds, it's going 12 m/s.  

This is the point at which the question wants us to compare them ... 3 seconds.  The bike is moving at 15 m/s and the car has sped up to 12 m/s. <em>The bike is moving faster than the car.</em>

If we hung around and kept watching for another second, the car would then be moving at 16 m/s, and would be moving faster than the bike.  But we lost interest after answering the question, and we left at 3 seconds.

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What is the resultant of the two vectors shown?
lianna [129]

Explanation:

The correct is (c). cuz, the tail of A and the tip of B will join

3 0
2 years ago
True or False? There is more downward force on a faster car than on a slower car when both
kondor19780726 [428]

Answer:

false

Explanation:

bc the faster car has more inertia (i dont think im correct)

not sure but feels like it

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3 years ago
Determine the speed
Paraphin [41]
Calculating the average speed is simple using the formula <span>speed = distance/time</span>
3 0
4 years ago
A 1000-kg car traveling north at 15 m/s collides with a2000-kg truck traveling east at 10 m/s. The occupants, wearing seat belts
Aleksandr-060686 [28]

Answer:

8.33 m/s, 36.87° North of East

Explanation:

m_n = Mass of car = 1000 kg

v_n = Velocity of car = 15 m/s

m_e = Mass of truck = 2000 kg

v_e = Velocity of truck = 10 m/s

M = Combined mass = 1000+2000 = 3000 kg

Momentum

p_n=m_nv_n\\\Rightarrow p_n=1000\times 15\\\Rightarrow p_n=15000\ kgm/s

Momentum of car traveling East is 15000 kgm/s

p_e=m_ev_e\\\Rightarrow p_n=2000\times 10\\\Rightarrow p_n=20000\ kgm/s

Momentum of truck traveling North is 20000 kgm/s

Angle

\theta=tan^{-1}\frac{p_n}{p_e}\\\Rightarrow \theta=tan^{-1}\frac{15000}{20000}\\\Rightarrow \theta=36.87^{\circ}

As the two vehicles are vectors, the resultant velocity is

(Mv)^2=p_n^2+p_e^2\\\Rightarrow v=\sqrt{\frac{p_n^2+p_e^2}{M^2}}\\\Rightarrow v=\sqrt{\frac{15000^2+20000^2}{3000^2}}\\\Rightarrow v=8.33\ m/s

Velocity of the two vehicles when they are locked together is 8.33 m/s and direction is 36.87° North of East

5 0
3 years ago
A 12-volt car battery uses about 660 amps. How much power does it use?
alexira [117]
We know, Power = Voltage * Current
P = 660 * 12 = 7920 watt

In short, Your Answer would be Option A

Hope this helps!
8 0
4 years ago
Read 2 more answers
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