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Paladinen [302]

4 years ago

14

What help in reversing direction of current of current

1 answer:

Novay_Z [31]4 years ago

3 0

Answer:

<em>To reverse the direction of an electric current, we simply reverse the voltage either automatically with the help of some switching circuitry or manually by changing the voltage source terminals connection. </em>

Explanation:

For electric current to flow, there must be a potential difference, usually referred to as the voltage. The electric current flow is analogous to the flow of water under the action of a pump, through a series of pipe connections. The voltage is similar to the driving action of the pump, and current flows the same way water flows. The resistance due to drag on the pipe wall is equivalent to electric resistance. For current to flow in the reverse direction, the voltage or rather, the potential difference is changed, causing the current to flow in the opposite direction. This can be done by switching the terminals of the voltage source, or by automatic means. The automatic switching can be done with a transistor based circuitry.

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3. Three blocks of masses m, 2m and 3m are suspended from the ceiling using ropes as shown in diagram. Which of the following co

Alja [10]

Answer:

The correct option is d: T₁ > T₂ > T₃.

Explanation:

Let's evaluate each tension.

<u>Case T₃.</u>

$T_{3} - W_{3} = 0$

For the system to be in equilibrium, the algebraic sum of the tension force (T) and the weight (W) must be equal to zero. The minus sign of W is because it is in the opposite direction of T.

$T_{3} = W_{3}$

Since W₃ = mg, where <em>m</em> is for mass and <em>g</em> is for the acceleration due to gravity, we have:

$T_{3} = W_{3} = mg$ (1) <u>Case T₂.</u>

$T_{2} - (T_{3} + W_{2}) = 0$

$T_{2} = T_{3} + W_{2}$ (2)

By entering W₂ = 2mg and equation (1) into eq (2) we have:

$T_{2} = T_{3} + W_{2} = mg + 2mg = 3mg$

<u>Case T₁.</u>

$T_{1} - (T_{2} + W_{1}) = 0$

$T_{1} = T_{2} + W_{1}$ (3)

Knowing that W₁ = 3mg and T₂ = 3mg, eq (3) is:

$T_{1} = 3mg + 3mg = 6mg$

Therefore, the correct option is d: T₁ > T₂ > T₃.

I hope it helps you!

6 0

3 years ago

Read 2 more answers

Which of the following quantities would be acceptable representations of weight? Check all that apply.

Oxana [17]

Only 12 lb and 1600 kN .

7 0

3 years ago

Which two phrases describe critical thinking skills used in the pursuit of<br> science?

SSSSS [86.1K]

Answer:

A. Expanding personal knowledge by reading articles from scientific

journals

B. Analyzing the different parts of a physical phenomenon to see

how they fit together

C. Predicting the impact that answering an important scientific

question would have on people

D. Developing a question that can be answered through testing or

observation

E. Developing logical arguments for providing incentives for

scientific research

6 0

3 years ago

Frictional forces acting on an object are often converted into __________ energy, which causes the temperature of the object to

d1i1m1o1n [39]

Heat energy. Friction causes heat build-up.

5 0

3 years ago

Read 2 more answers

What would be the kinetic energy k2q of charge 2q at a very large distance from the other charges? express your answer in terms

Pavlova-9 [17]

Answer:

$K_{2q}=\frac{7.76kq^2}{d}$

Explanation:

At the corner of the square, the potential energy of interaction of other charges with the charge 2q is given by $U_{2q}$

So

$U_{2q,i}=k\frac{(2q)(q)}{d}+k\frac{(2q)(5q)}{d}+k\frac{(2q)(-3q)}{\sqrt{2}d}=\frac{7.76 kq^2}{d}$

Also, since $K_{2q,i}=0$

The initial energy of the system is given by;

$E_i=U_{2q ,i}+K_{2q,i}=\frac{7.76kq^2}{d}+0=\frac{7.76kq^2}{d}$

Since $U_{2q,f}=0$

, the final energy of the system is obtained by

$E_f=U_{2q ,f}+K_{2q,f}=0+K_{2q,f}$

From the law of conservation of energy, $E_i=E_f$

Therefore, $K_{2q}=\frac{7.76kq^2}{d}$

7 0

3 years ago