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3 years ago

Which is an example of conduction?

Mathematics

2 answers:

BigorU [14]3 years ago

8 0

Answer:

Step-by-step explanation:

just took it

RSB [31]3 years ago

7 0

The answer is B) A hand is burned when touching a pot handle

Explanation: the first and last examples are not a direct exchange of heat from one to the other. Meaning that because the soup and stone are being surrounded by heat, they aren’t in as direct of contact as the hand. The hand touches directly to the hot handle and is immediately burned by the exchange of heat

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Andrea is selling candles as a fundraiser. She spent $50 on supplies for making the candles. She plans to sell the candles for $

Kipish [7]

Answer:

A reasonable range for the function is $[0, +\infty)$ .

Step-by-step explanation:

Revenues are positive quantities since Andrea is looking for money after expenses, so that reasonable range of the revenue function is $[0, +\infty)$ .

5 0

2 years ago

You bought a shirt with the price of $135.50, and the sale tax rate is 8.25% whats the sales tax

svp [43]

Answer:

11.18

Step-by-step explanation:

135.50 x .0825=11.18

6 0

2 years ago

Given h(x)=4x+3h , find h(-1)

satela [25.4K]

Answer:

h(-1) = -7

Step-by-step explanation:

use brackets while doing calculations
steps are clearly shown in the photo

hope this helped , if i helped you in acquiring the correct answer please tag me brainliest than... have a nice day ♡

7 0

2 years ago

Use the quadratic formula to solve the following equation -3x^2-x-3=0

tigry1 [53]

Answer:

$x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i$ are two roots of equation $-3 x^{2}-x-3=0$

Solution:

Need to solve given equation using quadratic formula.

$-3 x^{2}-x-3=0$

General form of quadratic equation is $a x^{2}+b x+c=0$

And quadratic formula for getting roots of quadratic equation is

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

In our case b = -1 , a = -3 and c = -3

Calculating roots of the equation we get

$\begin{array}{l}{x=\frac{-(-1) \pm \sqrt{(-1)^{2}-4(-3)(-3)}}{2 \times-3}} \\\\ {x=-\frac{1}{6} \pm\left(-\frac{\sqrt{-35}}{6}\right)}\end{array}$

Since $b^{2}-4 a c$ is equal to -35, which is less than zero, so given equation will not have real roots and have complex roots.

$\begin{array}{l}{\text { Hence } x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i \text { are two roots of equation - }} \\ {3 x^{2}-x-3=0}\end{array}$

8 0

3 years ago

What is the value of y in the equation -2y + 6 = -12?

Anit [1.1K]

Answer:

-2y + 6 = -12

Step-by-step explanation:

well the answer is 9, y=9 :)

PLEASE MARK ME BRAINLIEST!!!

6 0

1 year ago