Answer:
16/25
Step-by-step explanation:
4/10=40/100
24/100=24/100
40+24=64
64/100
16/25
No they won’t be.Consider the linear combination (1)(u – v) + (1) (v – w) + (-1)(u – w).This will add to 0. But the coefficients aren’t all 0.Therefore, those vectors aren’t linearly independent.
You can try an example of this with (1, 0, 0), (0, 1, 0), and (0, 0, 1), the usual basis vectors of R3.
That method relied on spotting the solution immediately.If you couldn’t see that, then there’s another approach to the problem.
We know that u, v, w are linearly independent vectors.So if au + bv + cw = 0, then a, b, and c are all 0 by definition.
Suppose we wanted to ask whether u – v, v – w, and u – w are linearly independent.Then we’d like to see if there are non-zero coefficients in the linear combinationd(u – v) + e(v – w) + f(u – w) = 0, where d, e, and f are scalars.
Distributing, we get du – dv + ev – ew + fu – fw = 0.Then regrouping by vector: (d + f)u + (-d +e)v + (-e – f)w = 0.
But now we have a linear combo of u, v, and w vectors.Therefore, all the coefficients must be 0.So d + f = 0, -d + e = 0, and –e – f = 0. It turns out that there’s a free variable in this solution.Say you let d be the free variable.Then we see f = -d and e = d.
Then any solution of the form (d, e, f) = (d, d, -d) will make (d + f)u + (-d +e)v + (-e – f)w = 0 a true statement.
Let d = 1 and you get our original solution. You can let d = 2, 3, or anything if you want.
Answer:
x = -1, x = 1
Step-by-step explanation:
Factor the equation. (It's a difference of squares, so we know the form will be (a-b)(a+b).)

Test this by FOILing it out, if you're unsure. This is something it can be good to memorize!
Set it equal to 0.

Separate the two parenthetical expressions by the Zero Product Property.

Solve for x!

Answer
N/A
Step-by-step explanation:
lets take a step into our imaginations, ok?
So when you divide, you're basically splitting the numerator into as many parts as the denominator.
imagine you have a chocolate bar, and it has 6 pieces and you want to split it evenly between your 3 friends.
you split it into three equal parts to get 2 pieces per person.
When you divide 0 by 0, your splitting 0 chocolate bars into 0 equal portions, which is why this problem isn't solvable.