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Kobotan [32]
3 years ago
6

Given f (x)= -x (x + 6), what is f (-3)?

Mathematics
1 answer:
Serggg [28]3 years ago
7 0

Answer:

9

Step-by-step explanation:

You might be interested in
Which expression has an estimated product of 45?<br>44.7x2.1<br>7.5x84<br>8.7x5.28<br>38.1 x 7.3​
Anni [7]

Answer: 8.7 x 5.28

We have to find that expression , which has an estimated product of

1.→44.7 x 2.1

2.→7.5 x 8.4

3.→8.7 x 5.28

4.→38.1 x 7.3

We will start from option 1.

→44.7 x 2.1

44.7 when estimated to nearest tenth=45

2.1, when estimated to nearest tenth=2

44.7 × 2.1=45×2=90

Option 2

7.5 x 8.4

7.5 when estimated to nearest tenth=8

8.4, when estimated to nearest tenth=8

⇒7.5 × 8.4=8×8=64

Option 3

8.7 × 5.28

8.7, when estimated to nearest tenth=9

5.28, when estimated to nearest tenth=5

⇒8.7 × 5.28=9×5=45

Option D

38.1 × 7.3

38.1 when estimated to nearest tenth=38

7.3, when estimated to nearest tenth=7

⇒38×7=266

Option C:⇒8.7 × 5.28 has an estimated product of 45

6 0
3 years ago
Read 2 more answers
What is 10/15 the same as
igomit [66]
If you simplify it, it would be that same as 2/3.
5 0
3 years ago
Identify the corresponding word problem given the equation: x + 12.50 = 55.75 A) For mowing the neighbor's yard, Jessy was paid
sergejj [24]
The answer is A.  because for you to find the answer you have to subtract so it would be 55.75-12.5=43.25
6 0
3 years ago
Read 2 more answers
A quality control expert at Glotech computers wants to test their new monitors. The production manager claims they have a mean l
Mariana [72]

Answer:

Step-by-step explanation:

Hello!

X: the lifespan of a new computer monitor of Glotech.

The average life is μ= 85 months and the variance δ²= 64

And a sample of 122 monitors was taken.

You need to calculate the probability that the sample mean is greater than 86.6 months.

Assuming that the variable has a normal distribution X~N(μ;δ²), then the distribution of the sample mean is X[bar]~N(μ;δ²/n)

To calculate this probability you have to work using the sampling distribution and the following formula Z= (X[bar]-μ)/δ/√n ~N(0;1)

P(X[bar]>86.6)= 1 - P(X[bar]≤86.6)

1 - P(Z≤(86.6-85)/(8/√122))= 1 - P(Z≤2.21)= 1 - 0.98645= 0.013355

The probability of the sample mean is greater than 0.013355

I hope this helps!

7 0
3 years ago
Kathy takes her cat to a veterinarian every year for a check-up. Last year, the difference in the cat's weight from teh year bef
Nataliya [291]
To find the difference in weights from two years ago, you will need to combine the 2 differences from the two years.  

-1.56 and 0.73 becomes -1.56 + 0.73.

To add a positive and a negative number you will subtract the absolute values of the numbers AND use the sign of the number with the bigger absolute value (negative) in your answer.

|-1.56| - |0.73|
1.56 - 0.73 = 0.83
-0.83

The cat lost 0.83 (-0.83) pounds over 2 years.
3 0
3 years ago
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