Answer: 8.7 x 5.28
We have to find that expression , which has an estimated product of
1.→44.7 x 2.1
2.→7.5 x 8.4
3.→8.7 x 5.28
4.→38.1 x 7.3
We will start from option 1.
→44.7 x 2.1
44.7 when estimated to nearest tenth=45
2.1, when estimated to nearest tenth=2
44.7 × 2.1=45×2=90
Option 2
7.5 x 8.4
7.5 when estimated to nearest tenth=8
8.4, when estimated to nearest tenth=8
⇒7.5 × 8.4=8×8=64
Option 3
8.7 × 5.28
8.7, when estimated to nearest tenth=9
5.28, when estimated to nearest tenth=5
⇒8.7 × 5.28=9×5=45
Option D
38.1 × 7.3
38.1 when estimated to nearest tenth=38
7.3, when estimated to nearest tenth=7
⇒38×7=266
Option C:⇒8.7 × 5.28 has an estimated product of 45
If you simplify it, it would be that same as 2/3.
The answer is A. because for you to find the answer you have to subtract so it would be 55.75-12.5=43.25
Answer:
Step-by-step explanation:
Hello!
X: the lifespan of a new computer monitor of Glotech.
The average life is μ= 85 months and the variance δ²= 64
And a sample of 122 monitors was taken.
You need to calculate the probability that the sample mean is greater than 86.6 months.
Assuming that the variable has a normal distribution X~N(μ;δ²), then the distribution of the sample mean is X[bar]~N(μ;δ²/n)
To calculate this probability you have to work using the sampling distribution and the following formula Z= (X[bar]-μ)/δ/√n ~N(0;1)
P(X[bar]>86.6)= 1 - P(X[bar]≤86.6)
1 - P(Z≤(86.6-85)/(8/√122))= 1 - P(Z≤2.21)= 1 - 0.98645= 0.013355
The probability of the sample mean is greater than 0.013355
I hope this helps!
To find the difference in weights from two years ago, you will need to combine the 2 differences from the two years.
-1.56 and 0.73 becomes -1.56 + 0.73.
To add a positive and a negative number you will subtract the absolute values of the numbers AND use the sign of the number with the bigger absolute value (negative) in your answer.
|-1.56| - |0.73|
1.56 - 0.73 = 0.83
-0.83
The cat lost 0.83 (-0.83) pounds over 2 years.
