Answer:
<h2>length = 89 m</h2>
Step-by-step explanation:
Area of a rectangle = l × w
where
l is the length
w is the width
From the question
Area = 6052 m²
width = 68 m
To find the length substitute the values into the above formula
6052 = 68l
Divide both sides by 68
We have the final answer as
<h3>length = 89 m</h3>
Hope this helps you
Point A: (－17＋5)÷2＝－6
Point B: (－6＋0)÷2=－3
Hope my answer helped u :)
Answer:
Step-by-step explanation:
You see that 't' is the 'argument' or 'input' to h: h(t). It is always safe to assume that t is the independent variable and h is the depend
the distance form X to Y is clearly -6 to 0 is 6 units, and 0 to 8 is 8 units, so 6 + 8 = 14 units.
now, for XZ and ZY we can simply use as stated, the distance formula to get those and then add them all to get the perimeter.
![\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ X(\stackrel{x_1}{-6}~,~\stackrel{y_1}{2})\qquad Z(\stackrel{x_2}{5}~,~\stackrel{y_2}{8})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ XZ=\sqrt{[5-(-6)]^2+[8-2]^2}\implies XZ=\sqrt{(5+6)^2+(8-2)^2} \\\\\\ XZ=\sqrt{121+36}\implies \boxed{XZ=\sqrt{157}} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~~~~~~~%5Ctextit%7Bdistance%20between%202%20points%7D%20%5C%5C%5C%5C%20X%28%5Cstackrel%7Bx_1%7D%7B-6%7D~%2C~%5Cstackrel%7By_1%7D%7B2%7D%29%5Cqquad%20Z%28%5Cstackrel%7Bx_2%7D%7B5%7D~%2C~%5Cstackrel%7By_2%7D%7B8%7D%29%5Cqquad%20%5Cqquad%20d%20%3D%20%5Csqrt%7B%28%20x_2-%20x_1%29%5E2%20%2B%20%28%20y_2-%20y_1%29%5E2%7D%20%5C%5C%5C%5C%5C%5C%20XZ%3D%5Csqrt%7B%5B5-%28-6%29%5D%5E2%2B%5B8-2%5D%5E2%7D%5Cimplies%20XZ%3D%5Csqrt%7B%285%2B6%29%5E2%2B%288-2%29%5E2%7D%20%5C%5C%5C%5C%5C%5C%20XZ%3D%5Csqrt%7B121%2B36%7D%5Cimplies%20%5Cboxed%7BXZ%3D%5Csqrt%7B157%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ Z(\stackrel{x_2}{5}~,~\stackrel{y_2}{8})\qquad Y(\stackrel{x_2}{8}~,~\stackrel{y_2}{2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ ZY=\sqrt{(8-5)^2+(2-8)^2}\implies ZY=\sqrt{9+36}\implies \boxed{ZY=\sqrt{45}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{perimeter}{14+\sqrt{157}+\sqrt{45}}\qquad \approx \qquad 33.2](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~~~~~~~%5Ctextit%7Bdistance%20between%202%20points%7D%20%5C%5C%5C%5C%20Z%28%5Cstackrel%7Bx_2%7D%7B5%7D~%2C~%5Cstackrel%7By_2%7D%7B8%7D%29%5Cqquad%20Y%28%5Cstackrel%7Bx_2%7D%7B8%7D~%2C~%5Cstackrel%7By_2%7D%7B2%7D%29%5Cqquad%20%5Cqquad%20d%20%3D%20%5Csqrt%7B%28%20x_2-%20x_1%29%5E2%20%2B%20%28%20y_2-%20y_1%29%5E2%7D%20%5C%5C%5C%5C%5C%5C%20ZY%3D%5Csqrt%7B%288-5%29%5E2%2B%282-8%29%5E2%7D%5Cimplies%20ZY%3D%5Csqrt%7B9%2B36%7D%5Cimplies%20%5Cboxed%7BZY%3D%5Csqrt%7B45%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7Bperimeter%7D%7B14%2B%5Csqrt%7B157%7D%2B%5Csqrt%7B45%7D%7D%5Cqquad%20%5Capprox%20%5Cqquad%2033.2)
