Answer:
B. 9
Step-by-step explanation:
We assume that ...
SU = ST +TU
133 = (9x-5) +(5x+12)
126 = 14x . . . . . subtract 7, collect terms
9 = x . . . . . . . . . divide by 14
In general when a firm produces nothing it still has to pay for the fixed costs while the variable costs are zero
Answer:
Randy had 13 books an Sandy had 7 books.
Step-by-step explanation:
20 - 3 = 17
30 - 17 = 13
13 x 2 = 26
26 + 4 = 30
13 + 7 = 20
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Answer:
<em>- 1/2 (or - 0.5) </em>
Step-by-step explanation:
so first, simplify by combining like terms.
so 8w-6w = 2w
so now we have
2w - 8 = 4w - 7
now we have to get the w's to one side of the equation so we can solve for it. so that mean we have to subtract 2w from both sides. 2w - 2w is 0. and then 4w - 2w = 2w. so now we have
-8 = 2w - 7
then to slowly start isolating w, add 7 to both sides of th equation. so now its
-1 = 2w
finally to get w by itself divide 2 from both sides.
and the answer is
-
= w
Answer:
8.20in³
Step-by-step explanation:
Given V = πr²h
r is the radius = 1.5in
h is the height = 6in
thickness of wall of the cylinder dr = 0.04in
top and bottom thickness dh 0.07in+0.07in = 0.14in
To compute the volume, we will find the value of dV
dV = dV/dr • dr + dV/dh • dh
dV/dr = 2πrh
dV/dh = πr²
dV = 2πrh dr + πr² dh
Substituting the values into the formula
dV = 2π(1.5)(6)•(0.04) + π(1.5)²(6) • 0.14
dV = 2π (0.36)+π(1.89)
dV = 0.72π+1.89π
dV = 2.61π
dV = 2.61(3.14)
dV = 8.1954in³
Hence volume, in cubic inches, of metal in the walls and top and bottom of the can is 8.20in³ (to two dp)
