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Verdich [7]
3 years ago
10

What is the relationship between a triangle and a square? Not numbers OK!!!!!!! Please help me

Mathematics
1 answer:
Fantom [35]3 years ago
4 0
Two congruent triangles make a square when you place their hypotenuses against each other/overlapping. The hypotenuse will be the square's diagonal. 
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An advertisement for a popular weight-loss clinic suggests that participants in its new diet program lose, on average, more than
Sedbober [7]

Testing the hypothesis, it is found that:

a)

The null hypothesis is: H_0: \mu \leq 10

The alternative hypothesis is: H_1: \mu > 10

b)

The critical value is: t_c = 1.74

The decision rule is:

  • If t < 1.74, we <u>do not reject</u> the null hypothesis.
  • If t > 1.74, we <u>reject</u> the null hypothesis.

c)

Since t = 1.41 < 1.74, we <u>do not reject the null hypothesis</u>, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

Item a:

At the null hypothesis, it is tested if the mean loss is of <u>at most 10 pounds</u>, that is:

H_0: \mu \leq 10

At the alternative hypothesis, it is tested if the mean loss is of <u>more than 10 pounds</u>, that is:

H_1: \mu > 10

Item b:

We are having a right-tailed test, as we are testing if the mean is more than a value, with a <u>significance level of 0.05</u> and 18 - 1 = <u>17 df.</u>

Hence, using a calculator for the t-distribution, the critical value is: t_c = 1.74.

Hence, the decision rule is:

  • If t < 1.74, we <u>do not reject</u> the null hypothesis.
  • If t > 1.74, we <u>reject</u> the null hypothesis.

Item c:

We have the <u>standard deviation for the sample</u>, hence the t-distribution is used. The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • s is the standard deviation of the sample.
  • n is the sample size.

For this problem, we have that:

\overline{x} = 10.8, \mu = 10, s = 2.4, n = 18

Thus, the value of the test statistic is:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{10.8 - 10}{\frac{2.4}{\sqrt{18}}}

t = 1.41

Since t = 1.41 < 1.74, we <u>do not reject the null hypothesis</u>, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

A similar problem is given at brainly.com/question/25147864

3 0
3 years ago
What is the domain of f?
larisa86 [58]

Answer:

\huge \boxed{\mathrm{A}}

Step-by-step explanation:

The domain of a function is all possible values for the value of x.

The denominator in a rational function cannot equal to 0.

x+2\neq 0

Subtracting 2 from both sides.

x\neq -2

The domain of the function is all real numbers except -2.

7 0
3 years ago
X^2 + 7x – 18 = 0<br> a<br> {–2, 9}<br> b<br> {–9, 2}<br> c<br> {2, 9}<br> d<br> {–2, –9}
Sedaia [141]

Answer:

b)-9,2

Step-by-step explanation:

x^2+7x-18=0

x^2+9x-2x-18=0

x(x+9)-2(x+9)=0

(x+9)(x-2)=0

therefore

x=-9

x=2

6 0
3 years ago
The function Q(t)=Qoe^kt May be used to model radioactive decay. Q representing the quantity remaining after t years; k is the d
rewona [7]

Answer:

A. -[ln(0.5)/6,300]

Step-by-step explanation:

Done on apex, it is correct.

5 0
3 years ago
Read 2 more answers
Find the measure for angle f<br><br> 46<br> 34<br> 122<br> 58
xxMikexx [17]

Answer:

\angle f = 122\degree

Step-by-step explanation:

\angle d = 58\degree (vertical angles)

\angle f+\angle d= 180\degree

(Interior angles on the same side of transversal)

\angle f+ 58\degree = 180\degree

\angle f = 180\degree-58\degree

\huge \orange {\boxed {\angle f = 122\degree}}

5 0
3 years ago
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