(i) Given radius r = 15 cm ∴ diameter d = 2 x 15 = 30 cm Circumference C = πd units = 227227 x 30 = 66076607 = 94.28 cm (ii) Given circumference C = 1760 cm 2πr = 1760 2 x 227227 x r = 1760 r = 1760×72×221760×72×22 = 160×72×2160×72×2 = 40 x 7 = 280 cm Diameter = 2 x r = 2 x 280 = 560 cm (iii) diameter d = 24m radius r = d2d2 = 242242 = 12 m Circumference C = 2 πr units = 2 x 227227 x 12 = 52875287 = 75.4 m Tabulating the results S. No. radius (r) diameter (d) circumference (C) (i) 15 cm 30 cm 94.28 cm (ii) 280 cm 560 cm 1760 cm (iii) 12 m 24
This is the concept of trigonometry, the distance from the foot of the ladder will be given by: tan theta=[opposite]/[adjacent] opposite=17 ft adjacent=x ft theta=37° thus tan 37=17/x x=17/tan 37 x=22.56 ft =22.6 ft (to the nearest 10th of a foot)
