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Alja [10]
3 years ago
15

Find the area of this irregular polygon.

Mathematics
1 answer:
nadya68 [22]3 years ago
8 0

Answer:

108 in^2

Step-by-step explanation:

Find the area of the rectangle on the bottom

A = l*w where the length is 8+6 and the width is 6

A = 14*6 =84

Find the area of the rectangle on the top

A = l*w where the length is 8 and the width is 9-6

A = 8*3 =24

Add the two areas together

84+24 = 108

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Please help me with this pleaseee
torisob [31]

Answer:

x = 88.2

Step-by-step explanation:

The angle at the top of the triangle = 90° - 10° = 80°

and the left side of the triangle is x ( opposite sides of a rectangle )

Using the tangent ratio in the right triangle

tan80° = \frac{opposite}{adjacent} = \frac{500}{x}

Multiply both sides by x

x × tan80° = 500 ( divide both sides by tan80° )

x = \frac{500}{tan80} ≈ 88.2

5 0
3 years ago
PLEASE HELP ASAP!!!!!! i’ll mark brainlest
Doss [256]

Answer: A) 5 x 1/2

Step-by-step explanation: 5 x 1/2 yields 2.5, which is also the answer to 5 / 2.

7 0
3 years ago
Read 2 more answers
HELP
TiliK225 [7]
I think it’s B I’m not sure about it but I hate wan I gat it wrong.
8 0
2 years ago
Solve with all work <br> −4(2 + 9) + 3 = 6 − 4( − 3)
ra1l [238]

Answer:

They do not equal eachother

Step-by-step explanation:

-4(2+9) + 3 = 6 - 4(-3)

-12 - 36 + 3 = 6 + 12

-45 = 18

3 0
3 years ago
What is the sum of all the integers between 19 and 77
victus00 [196]
Think of it this way: Lets add numbers in pairs, starting at the very outer 2 numbers (19 and 77)  then go in by one and add the second number and the second to last (20 and 76), then (21 and 75) and so on.  The sum of all of these pairs are all the same: 96.  How many 96s will we have?  Well since we're coming from each end toward the middle adding pairs we will have half the distance between 19 and 77, that is (77-19)/2 = 29.  So we can actually just take 96*29 = 2784.  This is the sum of all numbers between 19 and 77
7 0
3 years ago
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