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3 years ago

Find the area of this irregular polygon.

Mathematics

1 answer:

nadya68 [22]3 years ago

8 0

Answer:

108 in^2

Step-by-step explanation:

Find the area of the rectangle on the bottom

A = l*w where the length is 8+6 and the width is 6

A = 14*6 =84

Find the area of the rectangle on the top

A = l*w where the length is 8 and the width is 9-6

A = 8*3 =24

Add the two areas together

84+24 = 108

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3 years ago

Y= 4.6, 13.9, 21.6, ????

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Given triangle is a right angled triangle.

The legs of the triangle are 8 and y.

The hypotenuse of the triangle is x.

And the angle opposite to y is 60°

We need to determine the value of y.

Let us find the value of y using the tangent formula.

The formula for tan is given by

$tan \ \theta=\frac{opp}{adj}$

Since, we know that $\theta = 60^{\circ$ , $opp=y$ and $adj=8$

Substituting these values in the formula, we get,

$tan \ 60^{\circ}=\frac{y}{8}$

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Substituting the value of $\tan 60^{\circ}$ , we get,

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3 years ago

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Answer:

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