The answer to this question is -5
We have to add the equations in a clever way such that one of the variables cancels out. If you multiply the top one with 3 and the bottom one with 2, you cancel x. Like this:
3(2x+3y)=3*6 => 6x + 9y = 18
2(-3x+5y)=2*10 => -6x + 10y = 20
9y + 10y = 38 => 19y = 38 => y=2
If y=2 then 2x + 6 = 6 => x=0
The pair (0,2) is a solution.

a ) The domain:
x^4 - 16 x² ≥ 0
x² ( x² - 16 ) ≥ 0
x² - 16 ≥ 0
x² ≥ 16
x ∈ ( - ∞, - 4 ] ∪ [ 4 , + ∞ )b ) f ` ( x ) =

=
( 2 x³ - 16 x ) / √(x^4 - 16 x²)c ) The slope of the tangent line at x = 5:
f ` ( 5 ) = ( 2 * 125 - 16 * 5 ) / √ ( 625 - 400 ) = 170 / 15 = 34 / 3
The slope of the line normal to the graph at x = 5:
m = - 3 / 34
Answer: total comes to 4X - 12Y + 4
Step-by-step explanation:


7) You have the opposite. You need the adjacent.



x = 7.79289... =
<h2>7.8</h2><h2 />
8) You have the hypotenuse. You need the Opposite.


x = sin37 × 13
x = 7.8235... =
<h2>7.8</h2><h2 />
9) You have the hypotenuse. You need the opposite.


x = sin59 × 11
x = 9.4288.... =
<h2>9.4</h2><h2 />
10) You have the hypotenuse. You need the opposite.


x = sin53 × 11
x = 8.7459.... =
<h2>8.7</h2>