I'm assuming that the line is JKL in order of the points from left to right.
JK + KL = JL
(17-x) + (2x-7) = JL
Simplify.
10-x = JL
Answer:
The modulus of the complex number 6-2i is:
![|z|\:=2\sqrt{10}](https://tex.z-dn.net/?f=%7Cz%7C%5C%3A%3D2%5Csqrt%7B10%7D)
Step-by-step explanation:
Given the number
![6-2i](https://tex.z-dn.net/?f=6-2i)
We know that
where x and y are real and ![\sqrt{-1}=i](https://tex.z-dn.net/?f=%5Csqrt%7B-1%7D%3Di)
The modulus or absolute value of z is:
![|z|\:=\sqrt{x^2+y^2}](https://tex.z-dn.net/?f=%7Cz%7C%5C%3A%3D%5Csqrt%7Bx%5E2%2By%5E2%7D)
Therefore, the modulus of
will be:
![z=6-2i](https://tex.z-dn.net/?f=z%3D6-2i)
![z=6+(-2)i](https://tex.z-dn.net/?f=z%3D6%2B%28-2%29i)
![|z|\:=\sqrt{x^2+y^2}](https://tex.z-dn.net/?f=%7Cz%7C%5C%3A%3D%5Csqrt%7Bx%5E2%2By%5E2%7D)
![|z|\:=\sqrt{6^2+\left(-2\right)^2}](https://tex.z-dn.net/?f=%7Cz%7C%5C%3A%3D%5Csqrt%7B6%5E2%2B%5Cleft%28-2%5Cright%29%5E2%7D)
![=\sqrt{6^2+2^2}](https://tex.z-dn.net/?f=%3D%5Csqrt%7B6%5E2%2B2%5E2%7D)
![=\sqrt{36+4}](https://tex.z-dn.net/?f=%3D%5Csqrt%7B36%2B4%7D)
![=\sqrt{40}](https://tex.z-dn.net/?f=%3D%5Csqrt%7B40%7D)
![=\sqrt{2^2}\sqrt{2\cdot \:5}](https://tex.z-dn.net/?f=%3D%5Csqrt%7B2%5E2%7D%5Csqrt%7B2%5Ccdot%20%5C%3A5%7D)
![=2\sqrt{2\cdot \:5}](https://tex.z-dn.net/?f=%3D2%5Csqrt%7B2%5Ccdot%20%5C%3A5%7D)
![=2\sqrt{10}](https://tex.z-dn.net/?f=%3D2%5Csqrt%7B10%7D)
Therefore, the modulus of the complex number 6-2i is:
![|z|\:=2\sqrt{10}](https://tex.z-dn.net/?f=%7Cz%7C%5C%3A%3D2%5Csqrt%7B10%7D)
8/10 is greater than 63/100, it is grater because when u change them into a percentage 8/10 is higher
S=Selling price 135
V=Variable cost 75
F=Fixed cost 3300
Let quantity be Q
The formula to break even is
135Q-75Q-3300=0
Solve for Q
60Q-3300=0
60Q=3300
Q=3300/60
Q=50
So the store must sell 50 bicycles to break even
Hope it helps!