In the 3rd question, we are given the equation x ^ 3 + x ^ 2 + 2x + 24. One of the factors is x + 3. Now, we can use long division to find that the equation we have left is x^2 - 2x - 8. We can just factor this to get (x - 4) (x + 2). In the 3rd question, possible factors for the coefficient are 1, 2, -1, -2. Possible factors for the constant are 1, 7, -1, -7. Now, we can try out all of them. The possible factors are 1, 7, -1, -7, 2, 14, -2, -14.

7 0

2 years ago

Find the equation in standard form of the line passing through the points 3,-4 and 5,1

aliina [53]

Answer:

5x - 2y - 23 = 0

Step-by-step explanation:

Line is passing through the points $(3,\:-4)= (x_1, \:y_1) \: \&\: (5,\: 1)= (x_2,\:y_2)$

Equation of line in two point form is given as:

$\frac{y -y_1 }{y_1 -y_2 } = \frac{x -x_1 }{x_1 -x_2 } \\ \\ \therefore \: \frac{y -( - 4) }{ - 4 -1} = \frac{x -3 }{3 -5 } \\ \\ \therefore \:\frac{y + 4 }{ - 5} = \frac{x -3 }{ - 2 } \\ \\ \therefore \: \frac{y + 4 }{ 5} = \frac{x -3 }{ 2 } \\ \\ \therefore \: 2(y + 4) = 5(x - 3) \\ \therefore \: 2y + 8 = 5x - 15 \\ \therefore \: 5x - 15 - 2y - 8 = 0 \\ \red{ \boxed{ \bold{\therefore \: 5x - 2y - 23 = 0}}} \\ is \: the \: required \: equation \: of \: line \: in \: \\ standard \: form.$

7 0

2 years ago