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skelet666 [1.2K]

3 years ago

8

Damien , Jake , and Makayla shared a bowl of grapes . Damien ate x grapes . Jake ate 1 more than twice the number of grapes that

Damien ate . Makayla ate 5 fewer grapes than Damien ate . If there were 6 grapes left , how many grapes were in the bowl ?

2 answers:

vivado [14]3 years ago

8 0

Answer:

There were (4x + 2) grapes in the bowl

Step-by-step explanation:

Here, we are interested in calculating the total number of grapes in the bowl.

We have 3 people sharing the total

Damien are x grapes

Jake ate 1 more than twice what Damien and that is (1 + 2x) grapes

Makayla ate 5 fewer grapes than Damien: So what Makayla ate is (x-5) grapes

And now, we have 6 grapes left.

To find the total number of grapes in the bowl, we need to add up all what they ate plus what is left.

Mathematically, that would be;

x + 1 + 2x + x -5 + 6

= 4x + 2

lana66690 [7]3 years ago

3 0

Answer:

Write 400% as the ratio 400/100. To find an equivalent ratio, you know that 400 divided by 20 is 20, so 100 divided by 20 will give you the answer. 100 ÷ 20 = 5. Reza ate 5 grapes yesterday.

Step-by-step explanation:

Sample Answer

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2 years ago

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<img src="https://tex.z-dn.net/?f=4%20%5Ctimes%208%20%5E%7B2x%20%2B%201%3F%7D%20%20%3D%2032%20%5E%7Bx%20%2B%202%7D%20" id="TexFo

svet-max [94.6K]

Answer:

x = 5

Step-by-step explanation:

<u>__________________________________________________________</u>

<u>FACTS TO KNOW BEFORE SOLVING</u> :-

$a^x \times a^y = a^{x+y}$

In an equation , if the bases are same in both L.H.S. & R.H.S. then , the power of the bases on both the sides of equation should be equal. For e.g. : $a^x = a^y$ ⇒ $x = y$ [∵ Bases are equal on both the sides]

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$4 \times 8^{2x+1} = 32^{x+2}$

Lets express it in terms of 2.

$=> 2^2 \times 2^{3 (2x+1)} = 2^{5(x+2)}$

$=> 2^2 \times 2^{6x+3} = 2^{5x+10}$

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Here the bases on both the sides are equal. Hence ,

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Step-by-step explanation:

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3 years ago

Answer a, b and c. See image below

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Answer:

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b) In general if two fractions have the same denominator, then whichever fraction has the numerator closer to its denominator will be the largest fraction.

c) $\frac{7}{10} > \frac{9}{15}$ <em>or</em> $\frac{7}{10}$

Step-by-step explanation:

a) 3/5 < 4/5

Flip the sign and the placement of the fraction so 3/5 is less then 4/5.

b) In general if two fractions have the same denominator, then whichever fraction has the numerator closer to its denominator will be the largest fraction.

c) We need to change the denominators to a common denominator to compare the size of the two fractions:

$\frac{7}{10}$ × $\frac{3}{3}$ = $\frac{21}{30}$

$\frac{9}{15}$ × $\frac{2}{2}$ = $\frac{18}{30}$

The common denominators of the two fractions is 30. Comparing the two fractions:

$\frac{21}{30} >\frac{18}{30}$ <em>or</em> $\frac{18}{30}$

so we get: $\frac{7}{10} > \frac{9}{15}$ <em>or</em> $\frac{7}{10}$

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