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3 years ago

EX/Cupper(I)Iodide

Chemistry

1 answer:

matrenka [14]3 years ago

4 0

Explanation:

Copper sulphate reacts with potassium iodide to form cuprous iodide and iodine.

2CuSO

+4KI→Cu

↓+I

+2K

Thus, CuI

is not formed in this reaction.

Hence, the option B is incorrect and option A is correct.

The liberated iodine is titrated with sodium thiosulphate to form sodium tetrathionate.

2Na

→Na

+2NaI

Iodine is reduced and sodium thiosulphate is oxidized.

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In the following chemical equation, identify the products and reactants and indicate whether or not the equation is balanced. If

aleksandr82 [10.1K]

Answer:

a). The products are C6H12O6 O2 and the reactants are CO2 + H20 + (solar (light) energy)

b). The reaction chemical reaction is balanced from the number of moles of reactants and products

Explanation:

Through photosynthesis green plants, some protistans and some bacteria in the presence of energy from sunlight, produce glucose as well as oxygen from carbon dioxide and water.

It is a chemical reaction taking place in green plant to produce food which it uses to survive.

Photosynthesis requires carbon dioxide, water and solar energy in the leaves of a plant for it to take place.

The equation for photosynthesis is as follows: 6CO2 + 6H20 + (solar (light) energy) → C6H12O6 + 6O2

The products are C6H12O6 O2

and the reactants are CO2 + H20 + (solar (light) energy)

The reaction chemical reaction is balanced from the number of moles of reactants and products

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The Henry's law constant (kH) for O2 in water at 20°C is 1.28e-3 mol/l atm. How many grams of O2 will dissolve in 3.5 L of H2O t

Sophie [7]

Answer : The mass of $O_2$ dissolved will be, 0.2365 grams

Explanation :

First we have to calculate the concentration of $O_2$ .

As we know that,

$C_{O_2}=k_H\times p_{O_2}$

where,

$C_{O_2}$ = concentration of $O_2$ = ?

$p_{O_2}$ = partial pressure of $O_2$ = 1.65 atm

$k_H$ = Henry's law constant = $1.28\times 10^{-3}mole/L.atm$

Now put all the given values in the above formula, we get:

$C_{O_2}=(1.28\times 10^{-3}mole/L.atm)\times (1.65atm)$

$C_{O_2}=2.112\times 10^{-3}mole/L$

The concentration of $O_2$ = $2.112\times 10^{-3}mole/L$

Now we have to calculate the moles of $O_2$

$\text{Moles of }O_2=\text{Concentration of }O_2\times \text{volume of solution}$

$\text{Moles of }O_2=(2.112\times 10^{-3}mole/L)\times (3.5L)=7.392\times 10^{-3}mole$

Now we have to calculate the mass of $O_2$

$\text{Mass of }O_2=\text{Moles of }O_2\times \text{Molar mass of }O_2$

$\text{Mass of }O_2=(7.392\times 10^{-3}mole)\times (32g/mole)=0.2365g$

Therefore, the mass of $O_2$ dissolved will be, 0.2365 grams

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3 years ago

What type of solvent is needed to remove an oil stain?

Aliun [14]

The type of solvent that is needed to remove an oil stain would be an organic solvent. This is would dissolve the oil from the fabric to the solvent. Oil is nonpolar which would have the same polarity of an organic solvent. Hope this answers the question. Have a nice day.

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