A Cell with few energy needs would most likely contain a small number of Mitochondria.
- All cells require energy to function, but cells typically have significant energy needs that can only be met by the mitochondria, the cell's powerhouse.
- They transform glucose into ATP, a chemical with a huge energy storage capacity.
- Muscles have a large number of mitochondria, allowing them to react rapidly and powerfully to the body's ongoing need for energy.
- Macromolecules, defunct cell components, and microbes are all digested by lysosomes.
- Vacuoles are typically tiny and aid in the sequestration of waste.
- The ribosome, an intercellular structure consisting of both RNA and protein, is where a cell produces new proteins.
Therefore out of all these cell organelles, the cell has fewer mitochondria for less energy need.
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Answer:
AB + CD ----> AC + BD
Explanation:
If you think this reaction:
AB + CD ----> AC + BD
(Reactants) (Products)
All the statements are true.
This problem is requiring the empirical formula for CaCO₃, which is its molecular formula, and turns out to be equal, this is A. CaCO3 according to the following:
<h3>Empirical formulas:</h3><h3 />
In chemistry, molecular formulas show both the actual type and number of atoms in a chemical compound, based on the elements across the periodic table and the subscripts standing for the number of atoms in the compound.
However, the empirical formula is a reduced expression of the molecular one, which shows the minimum number of atoms in a compound after simplifying to the smallest whole numbers.
In such a way, since the given compound is CaCO₃ and both Ca and C have a one as their subscript, it is not possible to simplify any further and therefore the empirical formula equals the molecular one this time, making the answer to be A. CaCO3.
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Liters of gas at 14.7 psi: 3674 L
Explanation:
We can solve this problem by using Boyle's law, which states that:
"For an ideal gas kept at constant temperature, the pressure of the gas is inversely proportional to its volume"
Mathematically:
![pV=const.](https://tex.z-dn.net/?f=pV%3Dconst.)
where
p is the gas pressure
V is its volume
This law can also be rewritten as
![p_1 V_1 = p_2 V_2](https://tex.z-dn.net/?f=p_1%20V_1%20%3D%20p_2%20V_2)
Where:
is the initial pressure of the gas
is the initial volume of the gas
is the final pressure of the gas
is the final volume
Therefore, we can calculate the volume of gas corresponding to 14.7 psi of pressure:
![V_2=\frac{p_1 V_1}{p_2}=\frac{(3000)(18)}{14.7}=3674 L](https://tex.z-dn.net/?f=V_2%3D%5Cfrac%7Bp_1%20V_1%7D%7Bp_2%7D%3D%5Cfrac%7B%283000%29%2818%29%7D%7B14.7%7D%3D3674%20L)
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