The empirical formula of the metal oxide would be 
<h3>What is empirical formula?</h3>
Mass of scandium = 0.502g
Mass of scandium + oxygen = 0.768g
Mass of oxygen = 0.768 - 0.502 = 0.266g
Mole of scandium = 0.502/44.95 = 0.011
Mole of oxygen = 0.266/16 = 0.017
Divide by the lowest:
Scandium = 0.011/0.011 = 1
Oxygen = 0.017.0.011 = 1.5
Thus, the empirical formula of the compound would be 
or
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Answer:
Option A. 6.75 (6.20/85.6)
Explanation:
The following data were obtained from the question:
Initial volume (V1) = 6.2cm³
Initial concentration (C1) = 6.75M
Final volume (V2) = 85.6cm³
Final concentration (C2) =.?
The final concentration can be obtained by using the dilution formula as show below:
C1V1 = C2V2
6.75 x 6.2 = C2 x 85.6
Divide both side by 85.6
C2 = (6.75 x 6.2) /85.6
C2 = 6.75 (6.2 / 85.6).
Answer:
Explanation:
Fe₂O₃(s) + 3H₂(g) = 2Fe (s) + 3H₂O - 98.8 kJ .
one mole of ferric oxide reacts with 3 mole of hydrogen to give 2 mole of iron and 3 mole of water . 98.8 kJ of heat is absorbed .
Answer:
They would be proportional.
Explanation:
Electronegativity and ionization energy go hand in had. The more strongly an atoms pulls electrons to itself (electronegativity) the harder it will be to pick the electrons off (ionization energy). Therefore, the graphs would be proportional.
