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3 years ago

What is the greatest common factor of 14 and 6?

Mathematics

2 answers:

lutik1710 [3]3 years ago

6 0

Answer:

GCF (6, 14) = 2

Step-by-step explanation:

Factors of 6:

1, 2, 3, 6

Factors of 14:

1, 2, 7, 14

2 is the greatest number that 14 and 6 divides into.

Hope this helps.

sergij07 [2.7K]3 years ago

5 0

Answer:

gcf=2

Step-by-step explanation:

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alana and petra go to a used book sale, where every book is the same price. Alana buys 5 books and Petra buys 4 books. They run

Pachacha [2.7K]

After understanding the problem, formulate equations to determine the unknown. Let x be the price of one book. Equating Alana&Petra's expense with Angus' would be

5x + 4x +5 = 19x - 10

The 5 in the left side is needed because Angus' expense is $5 more. Also, the 10 on the right side represents the $10 discount. Solving the equation,

19x = 9x = 5+10
10x = 15
x = $1.5

Therefore, the book costs $1.5.

8 0

3 years ago

Complete the given diagram by dragging expressions to each leg of the triangle. Then, correctly complete the equation to derive

Nimfa-mama [501]

The equation to derive the distance d is $\sqrt{(x2-x1)^2+(y2-y1)^2}$ . The lengths of the other legs of the given triangle are (y2 - y1) and (x2 - x1).

<h3>What is the formula for calculating the distance between two points?</h3>

Consider the two points (x1, y1) and (x2, y2)

The formula used for calculating the distance between the two points is

distance = $\sqrt{(x2-x1)^2+(y2-y1)^2}$

<h3>Calculation:</h3>

Given that,

The triangle in the graph has vertices (x1, y1), (x2, y2), and (x2, y1)

Since this triangle makes 90°, it is a right-angled triangle.

Hypotenuse = (x1, y1) to (x2, y2), Adjacent = (x1, y1) to (x2,y1), and Opposite = (x2, y1) to (x2, y2).

Consider the length of the hypotenuse = d

So, using the distance formula, the length of the hypotenuse(d) is,

$d = \sqrt{(x2-x1)^2+(y2-y1)^2}$

And the lengths of the other two legs of the given triangle are,

Length of the adjacent side: (x1, y1) to (x2,y1)

= $\sqrt{(x2-x1)^2+(y1-y1)^2}$

= $\sqrt{(x2-x1)^2+0}$

= $(x2-x1)$

Length of the opposite side: (x2, y1) to (x2, y2)

= $\sqrt{(x2-x2)^2+(y2-y1)^2}$

= $\sqrt{0+(y2-y1)^2}$

= $(y2-y1)$

Therefore, the derived distances for the given triangle are:

$d=\sqrt{(x2-x1)^2+(y2-y1)^2}$ , (x2 - x1), and (y2 - y1).

Learn more about the distance between two points here:

brainly.com/question/661229

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4 0

1 year ago

What is the length of side a? Round to the nearest tenth of an inch. <br><br> Please and thank youuu

lord [1]

Answer:

using Pythagoras rule, 16^2 -7^2 =a^2

so 256-49 = 297.

√207 =14.38 to the nearest tenth of an inch is 14inch.which is your answer

6 0

2 years ago

Samantha’s college runs on a trimester schedule so she receives a bill 3 times a year for tuition. Each trimester costs $1,450,

SOVA2 [1]

Answer:

The total cost of Samantha's college degree is approximately $10,800.

Step-by-step explanation:

Cost of each trimester = $1,450

Now, total cost of fees per year = 3 x Cost of each trimester

= 3 x $1,450 = $4350

So, cost of fees in 2 complete years = 2 x $4,350 = $8,700

Also, Cost of books each trimester =$350

Now, total cost of books per year = 3 x Cost of each trimester

= 3 x $350 = $1,050

So, cost of books in 2 complete years = 2 x $1,050 = $2,100

So, total cost of Samantha's college = Total Trimester fees cost +Total books cost

= $8,700 + $2,100 = $10,800

Hence, the total cost of Samantha's college is approximately $10,800.

3 0

3 years ago

Read 2 more answers

I need to know the whole thing please help

aleksley [76]

Answer:

a) A student travelling to school on public transport: 15/52 or 0.231

b) A student walking to school: 16/52 or 0.308

c) A student not cycling to school: 43/52 or 0.827

Step-by-step explanation:

Total people = 52

Travel Method Frequency

Public Transport 12

Car 15

Cycle 9

Walk 16

Find the relative frequency of.

The formula used will be: $Relative\:Frequency=\frac{Given\: Frequency}{Size\: of\: sample \:space}$

a) A student travelling to school on public transport:

Given Frequency: 12

Size of sample space: 52

Apply formula: $Relative\:Frequency=\frac{Given\: Frequency}{Size\: of\: sample \:space}$

Fraction = 12/52

Decimal = 0.231

b) A student walking to school

Given Frequency: 16

Size of sample space. 52

Apply formula: $Relative\:Frequency=\frac{Given\: Frequency}{Size\: of\: sample \:space}$

Fraction = 16/52

Decimal = 0.308

c) A student not cycling to school.

We will consider all students except those who cycle.

12+15+16 = 43

Given Frequency: 43

Size of sample space. 52

Apply formula: $Relative\:Frequency=\frac{Given\: Frequency}{Size\: of\: sample \:space}$

Fraction = 43/52

Decimal = 0.827

6 0

3 years ago