T chart but thats all i can think of
The triangles that are similar would be ΔGCB and ΔPEB due to Angle, Angle, Angle similarity theorem.
<h3>How to identify similar triangles?</h3>
From the image attached, we see that we are given the Parallelogram GRPC. Thus;
A. The triangles that are similar would be ΔGCB and ΔPEB due to Angle, Angle, Angle similarity theorem.
B. The proof of the fact that ΔGCB and ΔPEB are similar pairs of triangles is as follow;
∠CGB ≅ ∠PEB (Alternate Interior Angles)
∠BPE ≅ ∠BCG (Alternate Interior Angles)
∠GBC ≅ ∠EBP (Vertical Angles)
C. To find the distance from B to E and from P to E, we will first find PE and then BE by proportion;
225/325 = PE/375
PE = 260 ft
BE/425 = 225/325
BE = 294 ft
Read more about Similar Triangles at; brainly.com/question/14285697
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Either to mirror, or to copy.
Answer:
9/25x^2 -25
Step-by-step explanation:
Answer:
Step-by-step explanation:
So to graph an inverse of the function given we have to switch the x and y values of the function:
So Ill do some points and the rest of the points the same process is applicable.
So our first point is (-1,1)
So our inverse point would be (1,-1)
The second point is (-2,2)
So our inverse point would be (2,-2)
The third point is (-3,3)
So our inverse point would be (3,-3)
Hope this helps!