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STatiana [176]
3 years ago
7

In ΔJKL, j = 7.2 cm, ∠L=74° and ∠J=89°. Find the length of l, to the nearest 10th of a centimeter.

Mathematics
1 answer:
wlad13 [49]3 years ago
3 0

Answer

6.9

Step-by-step explanation:

gave up on deltamath

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Do both of them for 50 points
erastovalidia [21]

Answer:

1) 5.44, 2) 3.9

Step-by-step explanation:

1) a/b + 2b - a^2 when a = 1.4 and b = 0.2

plug in the values:

1.4/0.2 + 2(0.2) - (1.4)^2 = 7 + 0.4 - 1.96 = 5.44

2) a[b-2c]^3 - d/e when a = 2, b = -0.75, c = -1, d = 0, e = -12 5/7 (rewritten to -89/7 = 12.71)

again, plug in the values:

2[-0.75-2(-1)]^3 - 0/12.71 = 2[1.25]^3 - 0 = 2[1.95] = 3.9

5 0
2 years ago
24<br> 23<br> 22<br> 21十<br> 20-<br> 4<br> 8<br> 12<br> 16
DochEvi [55]

Answer:

counted down

Step-by-step explanation:

it was counting up and went down by couting down in 2

7 0
2 years ago
HEEEEEEEEEEEEEEEEEEEEEEELLLLLLLLLLLLLLLLLLLLLLLLLPPPPPPPPPPPPPPPPPPP WITH ANSWER PLZZZZ
antiseptic1488 [7]
78 units squared add together 27.5+12+22+16.5 and you’ll get your answer for triangles it’s 1/2bh and for the rectangles it’s just bh. hope this helped!
6 0
3 years ago
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Y= -3x+4 standard form
Hunter-Best [27]
Y = -3x + 4 = Slope-intercept form
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8 0
3 years ago
Find the missing dimension use the scale factor 1:12 model 32 cm find the actual in m
gizmo_the_mogwai [7]

Given:

The scale factor is 1:12.

Dimension of model = 32 cm

To find:

The actual dimension in m.

Solution:

Let x be the actual dimension.

The scale factor is 1:12 and the dimension of model is 32 cm.

\dfrac{1}{12}=\dfrac{32}{x}

On cross multiplication, we get

x=32\times 12

x=384\ cm

x=3.84\ m             [\because 1\ m=100\ cm]

Therefore, the actual dimension is 3.84 m.

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2 years ago
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