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BARSIC [14]
3 years ago
11

Find the x-intercept of the rational function.

Mathematics
1 answer:
alexira [117]3 years ago
8 0

Answer:

What question are we supposed to answer

Step-by-step explanation:

Sorry I read the whole thing multiple times and couldn’t find what the question was

If you wanted the points to be graphed use Desmo calculator they graph the points for you:)

You might be interested in
Find the lcd. Add or subtract the fractions. Simplify if needed. (- 3/16) + (- 5/2)
Solnce55 [7]

Answer:

\boxed{-\frac{43}{16}}

.

Step-by-step explanation:

-\frac{3}{16}  + (-\frac{5}{2} )

= -\frac{3}{16}  - \frac{5}{2}

= \frac{-3 - 5(8)}{16}

= \frac{-3 - 40}{16}

= -\frac{43}{16}

8 0
3 years ago
Mrs. Carlyle bought a bag of nuts for her children. Phillip, Joy, Brent, and Preston took some from the bag.Phillip took 1/3. Jo
BARSIC [14]

Answer:

Originally there was 324 nuts in the bag.

Phillip took 108, Joy took 54, Brent took 81 and Preston took 10.

Step-by-step explanation:

Let's call the total amount of nuts N, and the number of nuts each child took by the initial of their name (Phillip will be P1 and Preston will be P2).

So we can write the following equations:

P1 = N/3

After removing N/3, the remaining nuts is (N - N/3):

J = (N - N/3)/4 = (2N/3)/4 = N/6

After removing N/6 from (N - N/3), the remaining nuts is (N - N/3 - N/6):

B = (N - N/3 - N/6)/2 = (N/2)/2 = N/4

P2 = 10

In the final there were 71 nuts remaining, so we have that:

N - N/3 - N/6 - N/4 - 10 = 71

N - N/3 - N/6 - N/4 = 81

N/4 = 81

N = 324 nuts

The amount of nuts took by each child is:

P1 = N/3 = 108 nuts

J = N/6 = 54 nuts

B = N/4 = 81 nuts

P2 = 10 nuts

8 0
4 years ago
What pair describes 6 and 4
viktelen [127]

Alternate interior angles I believe

4 0
3 years ago
If the
ahrayia [7]
It’s A bc it equals to 8
8 0
3 years ago
What is the multiplicity of each of the roots of the graph of
pantera1 [17]

Answer:

The correct option is;

C. -3, multiplicity 2; -1, multiplicity 1; 1, multiplicity 1

Please find attached the required function graph

Step-by-step explanation:

To solve the equation f(x) = 2·x⁴ + 12·x³ + 16·x² -12·x - 18, by graphing the function, we have;

x {}       F(x)

-4{}       30

-3{}       0

-2{}       6

-1{}        0

0 {}      -18

1{}         0

2{}       150

The shape of a graph with multiplicity of 2

Given that the graph bounces of the horizontal axis at the y-intercept at point x = -3, the factor (x - 3) must be a quadratic of the form (x - 3)², thereby having a multiplicity of 2 in the solution which are;

x = 1, -1, and, giving

(x - 1)·(x + 1)·(x - 3)² = 0

Therefore, the correct option is -3, multiplicity 2; -1, multiplicity 1; 1 multiplicity 1.

3 0
3 years ago
Read 2 more answers
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