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Oksana_A [137]
2 years ago
8

Please help what is it

Mathematics
1 answer:
Serggg [28]2 years ago
6 0

Answer: 4\sqrt{2}, 5.6

Or rounded it would be 6.

I hope I did this right. :)

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Translate to an algebraic statement.<br> "The quotient of twice a number and 7 is 20."
Genrish500 [490]

<u>Answer:</u>

  • Translation: 2x/7 = 20

<u>Step-by-step explanation:</u>

  • <em>When we listen to the word "quotient", it means the solution to a division problem. </em>
  • <em>An unknown number that has been multiplied by 2 is in the numerator because it came before the 7 in the statement. </em>
  • <em>The number "7" is in the denominator because it came after the 2x in the statement. </em>
  • <em>The word "is" represents an equal sign.</em>
  • <em>The solution to the division problem (quotient) is 20. </em>

<u><em>If we put these clues together, we get 2x/7 = 20 as our translated equation.</em></u>

<u>Hence, our algebraic statement is 2x/7 = 20. The key is to listen to the statement. </u>

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If a = 7 and b = 11, what is the measure of ∠B? (round to the nearest tenth of a degree) A) 32.5° B) 39.2° C) 50.5° D) 57.5°
Ilia_Sergeevich [38]

Answer:

D) 57.5°

Step-by-step explanation:

As the question is not complete. So, let's suppose it is a right angle triangle then, we can apply Pythagoras theorem to calculate the hypotenuse or the third side.

Pythagoras Theorem = c^{2} = a^{2} + b^{2}

a = 7 and b = 11

a^{2} = 49

b^{2} = 121

Plugging in the values, we will get:

c^{2} = 49 + 121

c^{2} = 170

c = \sqrt{170}

To calculate the unknown angle B, we can use law of sine.

Law of sine = \frac{a}{sinA} = \frac{b}{sinB} = \frac{c}{sinC}

So,

\frac{c}{sinC} = \frac{b}{sinB}

\frac{\sqrt{170} }{sin90} =  \frac{11}{sinB}

Sin90 = 1

sinB = \frac{11}{\sqrt{170} }

B = sin^{-1} (\frac{11}{\sqrt{170} })

B = 57.5°

8 0
3 years ago
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