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Sonja [21]
4 years ago
9

What are the domain restrictions of ?

Mathematics
1 answer:
Alchen [17]4 years ago
5 0
The denominator :  q² - 3q - 4 should be ≠ 0.
Let's find the zero values of this quadratic equation:

q' = [-b+√(b²-4.a.c)]/2.a    and   q'' = [-b-√(b<span>²-4.a.c)]/2.a

you will fond q' = 4  and q'' = -1

Then the restrictions are :

q </span>≠ 4 and q ≠ - 1 (1st answer)
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WILL MARK BRAINLIEST!!!
Stells [14]
Let y represent the yellow and x the red.
Y= 3x-5 is your equation
5 0
4 years ago
I kinda need some help as soon as possible I'll give you 20 points
Shtirlitz [24]

Answer:

x= 5

Step-by-step explanation:

20x=100

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8 0
3 years ago
Match each binomial expression with the set of coefficients of the terms obtained by expanding the expression.
user100 [1]

 explanation:

(A) (2x+y)^3=8 x^3 + 12 x^2 y + 6 x y^2 + y^3

Answer option C)  8, 12, 6, 1

B) (2x+3y)^4 = 16 x^4 + 96 x^3 y + 216 x^2 y^2 + 216 x y^3 + 81 y^4

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C) (3x+2y)^3 = 27 x^3 + 54 x^2 y + 36 x y^2 + 8 y^3

Answer option B) 27, 54, 36, 8

D)(x+y)^4 = x^4 + 4 x^3 y + 6 x^2 y^2 + 4 x y^3 + y^4

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8 0
3 years ago
Read 2 more answers
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Vlada [557]
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6 0
4 years ago
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AB passes through A(-3, 0) and B(-6, 5). What is the equation of the line that passes through the origin and is parallel to AB ?
Aleksandr [31]

Answer:

3y + 5x = 0

Step-by-step explanation:

The slope of the line = (y2-y1) / (x2-x1) = (5-0)/(-6-(-3))

= 5 / -3 = -5/3

Using the point-slope form , the line that passes through the origin and parallel to this line is

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y = -5/3 x

Multiply through by 3:-

3y = -5x

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3 0
3 years ago
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