What are the domain restrictions of ?
1 answer:
The denominator : q² - 3q - 4 should be ≠ 0.
Let's find the zero values of this quadratic equation:
q' = [-b+√(b²-4.a.c)]/2.a and q'' = [-b-√(b<span>²-4.a.c)]/2.a
you will fond q' = 4 and q'' = -1
Then the restrictions are :
q </span>≠ 4 and q ≠ - 1 (1st answer)
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The prime factorisation for 58 is 2 x 29
:)
The correct answer is C diagonal
Answer:9
Step-by-step explanation:
Because things are better guessed
If D is the midpoint of GH, then GH equals 2(DH) = 16
16 = 4x - 1
4x = 17
x = 17/4
x = 4.25
I think the answer would be B :)
