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TiliK225 [7]
3 years ago
6

Graph each line. Give the slope-intercept form for all standard.

Mathematics
1 answer:
Dafna11 [192]3 years ago
6 0

Answer:

Below

Step-by-step explanation:

y=mx+b

m=slope

b=y-intercept

Subtract x from both sides:

y=-x+3

You can place a point at (0,3) since that is the y-intercept.

You can also use the X-intercept which is found by making y zero: (3,0)

Then connect the points to create a line.

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A box weighs 90 grams. Write down, in terms of b, the weight of the boxes.
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Step-by-step explanation:

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Find the unknown coordinate so the line through the points has a given slope.
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A movie studio surveyed married couples about the types of movies they prefer. In the survey, the husband and wife were each ask
Aleksandr [31]

Using proportions, it is found that out of the next 75 couples asked, 49 will have at least one spouse that prefers action movies.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.

Researching this problem on the internet, it is found that out of 150 couples initially surveyed, 26 + 25 + 12 + 22 + 13 = 98 couples had at least one spouse preferring action movies, hence the proportion is:

p = 98/150 = 0.6533.

Out of the next 75 couples, the amount is:

A = 0.6533 x 75 = 49

Hence, out of the next 75 couples asked, 49 will have at least one spouse that prefers action movies.

More can be learned about proportions at brainly.com/question/24372153

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7 0
2 years ago
Kendall tracked the amount of water his windowsill plant needed each week over ten weeks. Her data is shown below.
Annette [7]

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4 0
3 years ago
Read 2 more answers
The half-life of cesium-137 is 30 years. Suppose we have a 20 mg sample.
Tju [1.3M]

Answer:

(a) A = (20mg)/(2^(t/30))

(b) 12.6mg

(c) 129.6years

Step-by-step explanation:

To calculate the amount remaining after a number of half-lives, n, we can make use of:

A = \frac{B}{2^n}

Where A = amount remaining

B = initial amount

n = \frac{t}{t_{0.5}}

(a) A = (20mg)/(2^(t/30))

(b) Mass after 20years

A = (20mg)/(2^(20/30)) ≈ 12.6mg

(c) After how long will only 1mg remain:

1mg = (20mg)/(2^(t/30))

20mg = {2^{\frac{t}{30}}

Taking log of both sides we have:

Log(20) = (t/30)log(2)

t/30 = (log(20))/(log(2)) ≈ 4.3

t/30 = 4.3

t = 30 x 4.3 ≈ 129.6years.

8 0
3 years ago
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