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SashulF [63]
3 years ago
11

If∠

Mathematics
1 answer:
andreev551 [17]3 years ago
3 0

Answer:

where is tge other half question?

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XHelp I need help on this math question I think its easy for others.
bixtya [17]

11. D Square pyramid

12. A Cube

7 0
3 years ago
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A total of 480 were sold for the school play. They were either adult tickets or students tickets. The number of student tickets
Talja [164]

Ok so basically, the number of student tickets is 3x, where x=the number of adult tickets sold. And we know that s(for student tickets)+x=480 total tickets sold. So if we replace s with 3x we have 3x+x=480, or 4x=480. We divide by 4 and get x=120, which is the amount of adult tickets sold.

5 0
4 years ago
The squirrels in our yard love black walnuts. 8% seem to prefer storing walnuts in our garage and 10% prefer to store them in ou
tatyana61 [14]
The answer is B, 14%
4 0
3 years ago
Applications 24. A rocket is launched into the air. Its height in feet, after x seconds, is given by the equation The starting h
SVEN [57.7K]

The given function is

h(x)=-16x^2+300x+20

According to this function, the starting height of the rocket is 20 feet because that's the initial condition of the problem stated by the independent term.

Additionally, we find the maximum height by calculating the vertex of the function V(h,k).

h=-\frac{b}{2a}

Where a = -16 and b = 300.

\begin{gathered} h=-\frac{300}{2(-16)}=\frac{300}{32}=\frac{150}{16}=\frac{75}{8} \\ h=9.375 \end{gathered}

Then, we find k by evaluating the function

\begin{gathered} k=-16(9.375)^2+300(9.375)+20 \\ k=-1406.25+2812.5+20=1426.25 \end{gathered}

Hence, the maximum height is 1426.25 feet.

At last, to know the time need to hit the ground, we just use h=9.375 and we multiply it by 2

t=2\cdot9.375=18.75

Hence, the rocket hits the ground after 18.75 seconds.

6 0
1 year ago
Graph the equation below by plotting the y-intercept and a second point on the line.
Solnce55 [7]
I don’t know if this helps but…

Slope: 2/3

Y-intercept: (0,-4)

7 0
2 years ago
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