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blondinia [14]
3 years ago
13

What is the amount of interest I earned on $4000 deposited in a savings account with 4% interest compounded annually after 4 yea

rs?
Mathematics
1 answer:
Dominik [7]3 years ago
6 0

Answer:

640 would be your interest.

Step-by-step explanation:

I'm not sure if htis is correct.. but to get interest u multiply rate part and time.

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Help me out 3 i need some help :(
Alenkinab [10]

Answer:

The first one

Step-by-step explanation:

Since only the first session is $10, it wouldn't be 10x.

The second session is $5, and it will never be $10 again, so $5 sessions are unlimited which would be 5x.

So the answer is y = 10 + 5x

(sorry if i didnt explain well)

8 0
3 years ago
What do y’all think the world is going to be in the future
geniusboy [140]

Answer:

No trees and just buildings.

Step-by-step explanation:

In the future, it is most likely to have some tall, bulky buildings.

Some scientists say that the future will be more about buildings and work spaces and less about trees.

So it is MORE likely for the future to have at least... 20 trees in the park. Also, less land. The land will be used to build buildings.

7 0
3 years ago
What is the value of 4(3x + 5) when x = 11?
navik [9.2K]

Answer:

152

Step-by-step explanation:

3(11)= 33

4(33+5)

4(33)=132

4(5)=20

132+20=152

5 0
3 years ago
Pls show work<br> 10 pts!!<br> Find x and y
Ipatiy [6.2K]

Answer:

hi

Step-by-step explanation:

8 0
3 years ago
Sea un cuadrado de 2 pulgadas de lado uniendo los puntos medios se obtiene otro cuadrado inscrito en el anterior si repetimos es
Ne4ueva [31]

Answer:

1) La serie geométrica formada es

4, 2, 1,..., ∞

2) La suma al infinito de las áreas de los cuadrados es 8 in.²

Step-by-step explanation:

1) El área del primer cuadrado, a₁ = 2² = 4 pulgadas²

El área del siguiente cuadrado, a₂ = (√ (1² + 1²)) ² = (√2) ² = 2 pulg²

El área del siguiente cuadrado, a₃ = ((√ (2) / 2) ² + (√ (2) / 2) ²) = 1 pulg²

Por lo tanto, la razón común, r = a₂ / a₁ = 2/4 = a₃ / a₂ = 1/2

Las áreas de los cuadrados progresivos forman una progresión geométrica como sigue;

4, 4×(1/2), 4 ×(1/2)²,...,4×(1/2)^{\infty}

De donde obtenemos la serie geométrica formada de la siguiente manera;

4, 2, 1,..., ∞

2) La suma de 'n' términos de una progresión geométrica hasta el infinito para -1 <r <1 se da como sigue;

S_{\infty} = \dfrac{a}{1 - r}

Por lo tanto, la suma de las áreas de los cuadrados hasta el infinito se obtiene sustituyendo los valores de 'a' y 'r' en la ecuación anterior de la siguiente manera;

La \ suma \ al \ infinito \ del \ cuadrado \ S_{\infty}  = \dfrac{4 \ in.^2}{1 - \dfrac{1}{2} } = \dfrac{4 \ in.^2}{\left(\dfrac{1}{2} \right)} = 2 \times 4 \ in.^2= 8 \ in.^2

La suma al infinito de las áreas de los cuadrados, S_{\infty} = 8 in.²

7 0
2 years ago
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