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Wittaler [7]
2 years ago
9

HELP ME WITH THIS IM DESPERATE!​

Mathematics
2 answers:
Tamiku [17]2 years ago
5 0
100 i know for sure!
Oliga [24]2 years ago
4 0

Answer:

i dont know but i think its 50

Step-by-step explanation:

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PLEASEEE HELP<br> Questions 4 and 5
Ilya [14]

Answer:

  • Given and explained below.

question 4

using sine rule:

\sf sinx = \frac{opp}{hyp}

\sf sinx = \frac{11}{13}

\sf x = sin^{-1}(\frac{11}{13} )

\sf x = 57.8

question 5

using cosine rule:

\sf cosx =\frac{adj}{hyp}

\sf cos(31) =\frac{x}{17}

\sf cos(31)*17 =x

\sf x = 14.6

4 0
2 years ago
Read 2 more answers
What is the value of X
erica [24]

Answer:

x=3

Step-by-step explanation:

the sides MJ and MK should be equal so 12x-24 = 4x

if you isolate x you get 3

3 0
3 years ago
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What is the absolute value of the complex number -4- V2/?
Dovator [93]

Answer:

3\sqrt{2}

Step-by-step explanation:

Given the complex number z = a + bi then the absolute value is

| z | = \sqrt{a^2+b^2}

Given - 4 - \sqrt{2} i, then absolute value is

\sqrt{(-4)^2+(-\sqrt{2})^2 }

= \sqrt{16+2}

= \sqrt{18} = \sqrt{9(2)} = 3\sqrt{2}

5 0
3 years ago
Which is the graph of f(x)=2(3)^x
likoan [24]

Let's plug the values and see which couple satisfy the equation: since y = 2\cdot 3^x, if we plug the values from the first option (x,y)=(1,6) we have


6 = 2\cdot 3^1 = 2\cdot 3


which is correct.


If we plug the values from the second option (x,y)=(1,9) we have


9 = 2\cdot 3^1 = 2\cdot 3


which is not correct


If we plug the values from the third option (x,y)=(2,9) we have


9 = 2\cdot 3^2= 2\cdot 9


which is not correct


If we plug the values from the fourth option (x,y)=(2,12) we have


12 = 2\cdot 3^2= 2\cdot 9


which is not correct


So, the answer is the first one.

3 0
3 years ago
An advertisement states that a can of paint will cover 480 square feet. How many gallons of paint are needed to cover 1,680 squa
zaharov [31]
480 goes into 1680 3 times 144 left bring down your 0. 480 goes into 2400 5 times. your answer is 35 cans of paint
3 0
3 years ago
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