Answer:
143.43 grams
Explanation:
First, balance the chemical equation.
2 Na + Cl₂ ⇒ 2 NaCl
Since chlorine is in excess, sodium is the limiting reagent. This means that you need to find out the stoichiometric relationship between sodium and sodium chloride. According to the equation, for every 2 moles of sodium, you produce 2 moles of sodium chloride. This makes the ratio 1:1 (2/2 = 1/1).
Next, you need to convert grams of sodium to moles using the molar mass.
(61.33 g) ÷ (22.99 g/mol) = 2.667 mol
Convert moles of sodium to moles of sodium chloride using the ratio.
(2.667 mol Na) × (1 mol NaCl/1 mol Na) = 2.667 mol NaCl
Convert moles of sodium chloride to grams using the molar mass.
(2.667 mol) × (58.44 g/mol) = 155.90 g
You have now found the theoretical yield. To find the actual yield, multiply the theoretical yield by the percent yield.
155.90 × 0.92 = 143.43
The chemist made 143.43 g of sodium chloride.
