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trapecia [35]
2 years ago
12

A. 0.12 B. 0.13 C. 0.14 D. 0.15 Explain why you chose the answer

Mathematics
1 answer:
blagie [28]2 years ago
8 0
The answer is C. 0.14
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One of the main contaminants of a nuclear accident, such as that at Chernobyl, is strontium-90, which decays exponentially at a
igor_vitrenko [27]

Answer: P=0.975^t


Step-by-step explanation:

We know that the general form of the exponential decay formula is


y=A(1-r)^t, where y is final amount remaining after t time, A is the original amount and r is the rate of decay


Now, the ratio of strontium-90 remaining, p , as a function of years, t , since the nuclear accident. P=\frac{A(1-0.02)^t}{A}=\frac{(0.975)^t}{1}

Hence, the ratio of remaining since the nuclear accident is P=0.975^t

3 0
3 years ago
Read 2 more answers
Is my answer correct or no? <br> ---&gt; show explanation &amp; details if i am wrong!!!
neonofarm [45]

Answer:

No, because the distance from the origin to point (7 , -7) is greater than the radius of the circle ⇒ 3rd answer

Step-by-step explanation:

From the graph of the circle

∵ The center of the circle F is at the origin

∴ F is (0 , 0)

∵ The circle passes through point (7 , 0)

- The length of the radius of the circle is the distance between

   the center of the circle and a point on the circle

∴ r is the distance between points (0 , 0) and (7 , 0)

∴ r=\sqrt{(7-0)^{2}+(0-0)^{2}}=\sqrt{49}=7

∴ The length of the radius of the circle is 7 units

Let us find the distance between point (7 , -7) and the origin (0 , 0)

  • If the distance is equal to the radius of the circle, then the point is on the circle
  • If the distance is greater than the radius, then the point is outside the circle
  • If the distance is less than the radius, then the point is inside the circle

∵ The distance =  \sqrt{(7-0)^{2}+(-7-0)^{2}}=\sqrt{49+49}=\sqrt{98}=7\sqrt{2}

∵ r = 7

∵ 7\sqrt{2} > 7

∴ The distance is greater than the radius of the circle

∴ Point (7 , -7) lies outside the circle

The correct answer is:

No, because the distance from the origin to point (7 , -7) is greater than the radius of the circle

<em>Your answer is not correct, the correct answer is the 3rd answer</em>

3 0
3 years ago
Need help on number 3! Ik the answer for number 4 only 3!!!
NeX [460]
1 degree is the answer
5 0
2 years ago
Are the quadrilaterals similar? If so, give the scale factor. If not, explain.
castortr0y [4]
These are not similar.  For them to be similar, they need to exist in proportion to each other for every single side.  The ratio of the 12:9 sides is 4:3 when reduced.  The ratio of the other 2 sides is 5:3.  They all have to have the same ratio for them to be similar.
7 0
3 years ago
Is it a function and whats the domain and range<br> Picture below
marishachu [46]
No, because using the vertical line test, two points touch on the same line
[3, 3]
[3,4]
8 0
3 years ago
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