Answer:
c. 2; no
Step-by-step explanation:
The inner product is the sum of the products of corresponding vector components. It is a scalar value, not a vector value.
(3, 5)·(4, -2) = (3)(4) +(5)(-2) = 12 -10 = 2
When the inner product is non-zero, the vectors are not perpendicular. (The yes answers with a non-zero value can be rejected out of hand.)
The appropriate choice is ...
2; no
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Since one equation has a negative y and the other has a positive y, I'm going to use those since they cancel each other out. Before that, the two y's need to be equal to each other.
x+2y=6
x-y=3
Multiply the bottom equation by two so then you have:
x+2y=6
2x-2y=6
The y's now cancel out:
x=6
2x=6
Add them together
3x=12
Divide
x=4.
To find y, plug x into either equation (*don't have to do both, but I will)
(4)+2y=6
(4)-y=3
Subtract four
2y=2
-y=-1
Divide each
2y/2 = 2/2
y=1
-y/-1 = -1/-1
y=1
The answer is:
x=4
y=1
I hope that helps!
Answer:
where −5 ≤ x ≤ 3
Step-by-step explanation:
The given function is 
.
We want to select the option that describes all the solutions to the parabola.
The domain of the parabola is −5 ≤ x ≤ 3.
This means that any x=a on −5 ≤ x ≤ 3 that satisfies (a,f(a)), is a solution.
This can be rewritten as 
Therefore for x belonging to −5 ≤ x ≤ 3, all solutions are given by:
where −5 ≤ x ≤ 3.
Answer:
If simplifed, it'll be -v
Step-by-step explanation:
