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3 years ago

7

I WILL GIVE BRAINLIEST FOR WHOEVER ANSWERS FIRST! - SORRY IF I DIDN'T MARK U BRAINLIEST BECAUSE IT WOULDN'T LET ME LAST TIME. I

REALLY NEED SOMEONE TO TALK TOO... please it is really important.

2 answers:

Elden [556K]3 years ago

7 0

Answer:

What do you need to talk about?

Step-by-step explanation:

Umnica [9.8K]3 years ago

7 0

Answer:

wait what do u need?

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Sean walks ¾ of a mile in 15 minutes. At the same pace, how far can Sean walk in 1 hour and 20 minutes? Explain

Pavlova-9 [17]

1 hr plus 20 minutes
Then that answer divided by 15
Then that answer multiply by 3/4

5 0

3 years ago

If you ran exactly one mile, how many feet did you run

elena-s [515]

Solution:

we have been asked to find

If you ran exactly one mile, how many feet did you run.

It mean , we will have to convert miles in feet.

As we know that

1 mile is equivalent to 5280 feet.

Hence , we can use this conversion to get the exact value of miles in feet.

If you ran exactly one mile,it mean you ran exactly for 5280 feet.

4 0

3 years ago

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The endpoints of a diameter of a circle are (6,2) and (−2,5) . What is the standard form of the equation of this circle?

Paul [167]

Answer:

The standard form of the given circle is

$(x-2)^2+(y-\frac{7}{2})^2=73$

Step-by-step explanation:

Given that the end points of a diameter of a circle are (6,2) and (-2,5);

Now to find the standard form of the equation of this circle:

The center is (h,k) of the circle is the midpoint of the given diameter

midpoint formula is $M=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

Let $(x_{1},y_{1})$ and $(x_{2},y_{2})$ be the given points (6,2) and (-2,5) respectively.

$M=(\frac{6-2}{2},\frac{2+5}{2})$

$M=(\frac{4}{2},\frac{7}{2})$

$M=(2,\frac{7}{2})$

Therefore the center (h,k) is $(2,\frac{7}{2})$

now to find the radius:

The diameter is the distance between the given points (6,2) and (-2,5)

$d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

$=\sqrt{(-2-6)^2+(5-2)^2}$

$=\sqrt{(-8)^2+(3)^2}$

$=\sqrt{64+9}$

$=\sqrt{73}$

Therefore the radius is $\sqrt{73}$

i.e., $r=\sqrt{73}$

Therefore the standard form of the circle is

$(x-h)^2+(y-k)^2=r^2$

Now substituting the center and radiuswe get

$(x-2)^2+(y-\frac{7}{2})^2=(\sqrt{73})^2$

$(x-2)^2+(y-\frac{7}{2})^2=73$

Therefore the standard form of the given circle is

$(x-2)^2+(y-\frac{7}{2})^2=73$

5 0

3 years ago

Write the expression in words 35-(14 + 17)

Genrish500 [490]

The sum of fourteen and seventeen subtracted from thirty five

8 0

3 years ago

Can someone help me with this I keep getting an answer that it doesn’t give me! And explain it!!!

Ira Lisetskai [31]

$(100\%-15\%-25\%)\cdot240=60\%\cdot240=144$

6 0

3 years ago

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