We have been given that a person places $6340 in an investment account earning an annual rate of 8.4%, compounded continuously. We are asked to find amount of money in the account after 2 years.
We will use continuous compounding formula to solve our given problem as:
, where
A = Final amount after t years,
P = Principal initially invested,
e = base of a natural logarithm,
r = Rate of interest in decimal form.
Upon substituting our given values in above formula, we will get:
Upon rounding to nearest cent, we will get:
Therefore, an amount of $7499.82 will be in account after 2 years.
Im assuming your supposed to find like terms soo... as my final answer i got 11m-3n-13
77.5d + .14m
m = 425
.14 * 425 = 59.5
77.5d + 59.5 ≤ 230
77.5d ≤ 170.5
d ≤ 170.5/77.5
d ≤ 2.2
if they only take payment for whole days, he has 2 whole days
Answer:
? = 14
Step-by-step explanation:
let us say that ? = x
7^x * 7^5^4 = 7^34
When you have a power to a power you multiply
7^x * 7^20 = 7^34
when you multiply common bases you add the power. since all the bases aer the same just look at the power
7^34-20 = 7^x
7^14 = 7^x
Its true for integers if you are using the associative property in addition or multiplication ONLY.
