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Ivanshal [37]
3 years ago
13

The length of a rectangle is represented by the function L(x) = 2x. The width of that same rectangle is represented by the funct

ion W(x) = 8x2 − 4x + 1. Which of the following shows the area of the rectangle in terms of x?
(L + W)(x) = 8x2 − 2x + 1
(L + W)(x) = 8x2 − 6x + 1
(L ⋅ W)(x) = 16x3 − 4x + 1
(L ⋅ W)(x) = 16x3 − 8x2 + 2x
Mathematics
2 answers:
denis-greek [22]3 years ago
6 0
I believe the correct answer from the choices listed above is the last option. The area of the rectangle can be calculated by the expression given as <span>(L ⋅ W)(x) = 16x3 − 8x2 + 2x. We obtian this as follows:
</span>

Area = LW
Area = 2x (<span>8x^2 − 4x + 1)
Area = 16x^3 - 8x^2 + 2x</span>
Dahasolnce [82]3 years ago
3 0

Answer: Area = LW

Area = 2x (8x^2 − 4x + 1)

Area = 16x^3 - 8x^2 + 2x

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Andre45 [30]

Answer:

the equation of the line is:

y=-2x+-3

3 0
3 years ago
Given the following absolute value function find the range. ƒ(x) = |x + 5| - 8
balandron [24]
The result of an absolute value operation is never negative. So the smallest that the expression |x+5| can be is 0. 

Tacking on "-8" to |x+5| leads to |x+5|-8

The range of this is [-8, infinity) since the smallest |x+5|-8 can be is -8. All I did was subtract 8 from the smallest value of |x+5|

Final Answer: choice C)
7 0
2 years ago
Find the equation of the line perpendicular to y=-4x+3 that also intersects the point (8,1)
Fudgin [204]

Answer:

-1

Step-by-step explanation:

They already did the opposite reciprocal for you.

They have it in the form y=\frac{1}{4}x+b now.

To find b you just enter (x,y)=(8,1).

Let's do that.

1=\frac{1}{4}(8)+b

1=2+b

Subtract 2 on both sides:

-1=b

b=-1

4 0
3 years ago
Read 2 more answers
= The average score of Karl's first four math tests is 72 points. After the fifth and the sixth tests, his average score increas
mylen [45]

Answer:

83 points

Step-by-step explanation:

-The formula for average is given as:

\bar X=\frac{1}{n}\sum{x_i}\\\\x_i=Individual \ Test \ scores\\n=number \ of \ scores

Let a be his 5th score and (a+4) of the 6th

#We subtract the sum of the first 4 tests from the 6, to get the sum of the 5th and 6th tests:

(6^{th}+5^{th})=\bar X n_6-\bar X n_4\\\\=75\times 6-72\times 4\\\\=162

#We substitute for the 5th and 6th to solve a:

5^{th}=a\\6^{th}=a+4\\\\a+(a+4)=162\\\\2a=158\\\\a=79\\\\6^{th}=a+4=79+4=83

Hence, Karl score 83 points in his 6th test.

5 0
3 years ago
An electric pole is 10m high if it's shadow is 10×√3 in length find the elevation ofthe sum
lianna [129]
First, Look at the attached picture as a reference.

Now, using Pythagoras theorem, 

AC^2=AB^2+BC^2 \\\\AC=\sqrt{AB^2+BC^2 }\\\\AC=\sqrt{10^2+(10\sqrt3)^2}\\\\ AC = \sqrt{100+300}\\\\AC=\sqrt{400}\\\\AC=20~in.

Now, lets find the elevation of the sun.

<span> </span>tan\theta =  \frac{AB}{BC} \\\\ tan\theta =  \frac{10}{10\sqrt3} \\\\ \theta = tan^{-1} \left(\frac{10}{10\sqrt3}\right) \\\\ \boxed{\theta = 30  \°}

∴ The elevation of the sun is 30°

 

6 0
3 years ago
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