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GenaCL600 [577]
3 years ago
14

Chris will work as a landscaper over the summer. He buys $240 worth of supplies and will spend $10 each week on advertising. If

he earns $80 each week, how long will it take him to make a profit?
Identify:

Strategize:

Set up:

Solve:

Check:
Mathematics
1 answer:
babunello [35]3 years ago
8 0
I think he’s spending to much in supplies and to little in advertising like what advertising are you buying with $10 and i think he earns to little so he should quit his job
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FInd the length of DB and CD. Please help!
Lerok [7]

Step-by-step explanation:

DB length = 5 1/4 + 2/3

=21/4 + 2/3

= 63/12 + 8/12 = 71/12

CD length = 5 1/4 -2 = 3 1/4

3 0
3 years ago
Solve for x . 8x-3 &amp; 4x+3 <br> 8x-3+4x+3=180<br> ?x+_=180
STALIN [3.7K]

Answer:

x = 15

Step-by-step explanation:

the 2 angles are a linear pair and sum to 180° that is

8x - 3 + 4x + 3 = 180

12x = 180 ( divide both sides by 12 )

x = 15

6 0
2 years ago
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Calculate the average velocity of a dancer who moves 5 m toward the left of the stage over the course of 15 s.
Neko [114]

Answer:

Divide the distance by the time and get average velocity in units of m/s.  The direction is to the left.

8 0
3 years ago
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Find the slope of the line that is ​(a) parallel and ​(b) perpendicular to the line through the pair of points.
ddd [48]

Answer:

a) The slope of the line is parallel to the another line m=4

b) The slope of the line is perpendicular to the another line m=\frac{-1}{4}

Step-by-step explanation:

Step1:-

<u>Slope of a line</u><u> :-</u>

If θ is the inclination of a line 'l' then tanθ is called the slope or gradient of the line 'l'.The slope of a line is denoted by m=tanθ

The slope of a line given two points m=\frac{y_{2}-y_{1}  }{x_{2} -x_{1} }

<u>Parallel lines:-</u>

<u>Two </u>non-vertical lines are parallel if and only if their slopes are parallel

<u>Perpendicular lines:-</u>

<u>Two </u>non-vertical lines are perpendicular to each other if and only if their slopes are negative reciprocals of each other.

m_{2} = \frac{-1}{m_{1} } \\

<u>Step 2</u>:-

a)The slope of a line when given two points (-1,-4) and (0,0)

m = \frac{0-(-4)}{0-(-1)} =4

<u>Two </u>non-vertical lines are parallel if and only if their slopes are parallel

m_{1} = m_{2}

Therefore the slope of the line that is parallel to the another line

m_{1} =m_{2} =4

<u>Step 3</u>:-

b) <u>Two </u>non-vertical lines are perpendicular to each other if and only if their slopes are negative reciprocals of each other.

m_{2} = \frac{-1}{m_{1} } \\

m_{2} =\frac{-1}{4}

Therefore the slope of the line is perpendicular to the another line is

m=\frac{-1}{4}

3 0
3 years ago
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F(x)= x-2/ x-4
hodyreva [135]

Answer:

The discontinuity is x = 4

There no holes

The equation of the vertical asymptote is x = 4

The x intercept is 2

The equation of the horizontal asymptote is y = 1

Step-by-step explanation:

* Lets explain the problem

∵ f(x)=\frac{x-2}{x-4}

- To find the point of discontinuity put the denominator = 0 and find

 the value of x

∵ The denominator is x - 4

∵ x - 4 = 0 ⇒ add 4 to both sides

∴ x = 4

* The discontinuity is x = 4

- A hole occurs when a number is both a zero of the numerator

 and denominator

∵ The numerator is x - 2

∵ x - 2 = 0 ⇒ add 2 to both sides

∴ x = 2

∵ The denominator is x - 4

∵ x - 4 = 0 ⇒ add 4 to both sides

∴ x = 4

∵ There is no common number makes the numerator and denominator

   equal to 0

∴ There no holes

- Vertical asymptotes are vertical lines which correspond to the zeroes  

  of the denominator of the function

∵ The zero of the denominator is x = 4

∴ The equation of the vertical asymptote is x = 4

- x- intercept is the values of x which make f(x) = 0, means the

 intersection points between the graph and the x-axis

∵ f(x) = 0

∴ \frac{x-2}{x-4}=0 ⇒ by using cross multiplication

∴ x - 2 = 0 ⇒ add 2 to both sides

∴ x = 2

* The x intercept is 2

- If the highest power of the numerator = the highest power of the

 denominator, then the equation of the horizontal asymptote is

 y = The leading coeff. of numerator/leading coeff. of denominator

∵ The numerator is x - 2

∵ The denominator is x - 4

∵ The leading coefficient of the numerator is 1

∵ The leading coefficient of the denominator is 1

∴ y = 1/1 = 1

* The equation of the horizontal asymptote is y = 1

6 0
3 years ago
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