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kirill115 [55]
3 years ago
13

Which equation represents a circle with a center at -3, -5) and a radius of 6 units?

Mathematics
1 answer:
vesna_86 [32]3 years ago
7 0

Answer:

(x+3)²+(y+5)² = 36

Step-by-step explanation:

The general equation of a circle is expressed as;

(x-a)²+(y-b)² = r² where;

(a, b) is the centre of the circle

r is the radius of the circle

Given

Centre (-3, -5)

a = -3 and b = -5

radius r = 6units

Substitute

(x-a)²+(y-b)² = r²

(x-(-3))²+(y-(-5))² = 6²

(x+3)²+(y+5)² = 36

hence the required equation is (x+3)²+(y+5)² = 36

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\large \boxed{ {(x - h)}^{2}  +  {(y - k)}^{2}  =  {r}^{2} }

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The question has already given the information we need, which are:

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Since the center is (h,k) - therefore the center is at h = 0 and k = 8 making it (h,k) = (0,8).

Substitute the values in the equation:

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