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2 years ago

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if a girl has 15 dirhums to buy lunch. she wants to buy one of each of the foods. how much more money will she need to buy lunch

?

1 answer:

gizmo_the_mogwai [7]2 years ago

4 0

How many “ foods “ are there tho?

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horrorfan [7]

Answer:

The answer is 6

Step-by-step explanation:

What you do is this.

3/9 times 18/1 because you need to make 18 a fraction and then multiply. And you will get 6

8 0

3 years ago

3/4x - 6y = 18<br>what's the x intercepts and y intercepts?

mash [69]

Answer:

X: (24,0)

Y(0,-3)

Step-by-step explanation:

X-intercept:

.75x-6y=18

plug in 0 for y

.75x-6(0)=18

divide by .75

x=24

(24,0)

Y-intercept:

plug in 0 for x

.75(0)-6y=18

divide by -6

y=-3

(0,-3)

7 0

3 years ago

891 is 99% of what amount?

vaieri [72.5K]

Answer:

900

Step-by-step explanation:

Hope this helps!

6 0

3 years ago

Read 2 more answers

1100 students attend Ridgewood Junior High School. 4% of students bring their lunch to school everyday. How many students brough

Triss [41]

Answer:

the answer is 44 students.

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

How to prove this???

swat32

$\cos^3 2A + 3 \cos 2A \\
\Rightarrow \cos 2A (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (1 - \sin^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - \sin^2 2A) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - (2\sin A \cos A)(2\sin A \cos A)) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - 4\sin^2 A \cos^2 A) \\ 
\Rightarrow 4(\cos^2 A - \sin^2 A) (1 - \sin^2 A \cos^2 A) 
$

go to right side now

$4( \cos^6 A - \sin^6 A)\\
\Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A)$

use $x^3 - y^3 = (x-y)(x^2 + xy + y^2)$ and $x^3 + y^3 = x^2 - xy + y^2$

$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A) \\
\Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\
~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A)$

so $\sin^2 A + \cos^2 A = 1$

$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\ ~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 + \cos A \sin A )(1- \cos A \sin A ) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \cos^2 A \sin^2 A )\\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \sin^2 A \cos^2 A ) \\
 \Rightarrow Left hand side$

4 0

2 years ago