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1 year ago

Two communications companies offer calling plans. With Company X, it costs 30¢ to connect and then

Mathematics

1 answer:

tensa zangetsu [6.8K]1 year ago

8 0

<h3>Answer: n+15</h3>

=======================================================

Explanation:

n = number of minutes
cost of company X = 3n+30
cost of company Y = 2n+15

To find out how much more company X charges, we subtract the two cost expressions

CompanyX - CompanyY = (3n+30)-(2n+15) = 3n+30-2n-15 = n+15 which is the final answer.

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An example:

Let's say you talk on the phone for n = 20 minutes.

Company X would charge you 3n+30 = 3*20+30 = 90 cents

Company Y would charge you 2n+15 = 2*20+15 = 55 cents

The difference of which is 90-55 = 35 cents.

If you plugged n = 20 into the n+15 expression we got, then n+15 = 20+15 = 35 matches up with the previous 35 cents.

This example helps confirm the answer. I'll let you try out other examples.

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A women standing on a cliff at the edge of the ocean spots a raft. Her eye level is 65 feet above sea level and the angle of dep

Aliun [14]

Answer:

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Step-by-step explanation:

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2 years ago

Please help! Giving points :)!

velikii [3]

Answer:

Step-by-step explanation:

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1 year ago

3 letters without replacement 4 letters A B C D how many ways can this be done if the order of the choices matters

Veseljchak [2.6K]

Answer:

Since the order of choice matters, we will permute the values. a bit more explanation for this:

If the order of choice did NOT matter, ABC and BCA will be counted as one since order of choice does NOT matter

Since order of choice does matter, ABC , BCA and CAB are all different possibilities for the arrangement of the same 3 letters

Since we have 3 slots:

___ ___ ___

Now, for the first slot. You can out either one if the 4 alphabets in the first slot since no slot has been used as of now

So:

_4_ ___ ___

**Keep in mind that the 4 is the possible number of values this slot can have**

Now that one slot has been used, one of the 4 alphabets has been used and since we are not allowed to repeat the same alphabets, we are left with 3 more alphabets

we can put any one of the 3 alphabets in this second slot, Hence:

_4_ _3_ ___

Now that 2 of the 4 alphabets have been used, we are left with only 2 alphabets, so there are only 2 possible alphabets for slot 3

Therefore:

_4_ _3_ _2_

Now that we know the possible alphabets for all 3 slots, we will multiply them with each other to get the total possible number of 3 - alphabet words we can make with 4 alphabets

Total possible words = 4 * 3 * 2

Total possible words = 24

We could've used the formula for Permutation as well

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2 years ago

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elixir [45]

a and b i hope this is correct

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2 years ago

Read 2 more answers

Natalia solved the problem 74.4/12=6.2. complete the model with partial products check Natalia's work using multiplication

tia_tia [17]

Answer:

Natalia's work is wrong.

Step-by-step explanation:

Natalia divided a decimal number by an entire number. Since division is a operation derived from multiplication, the best approach to check if work was good is multiplying the given result by denomination, that is:

1) $x = 6.2\times 12$ Given.