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zalisa [80]
2 years ago
15

Two communications companies offer calling plans. With Company X, it costs 30¢ to connect and then

Mathematics
1 answer:
tensa zangetsu [6.8K]2 years ago
8 0
<h3>Answer:  n+15</h3>

=======================================================

Explanation:

  • n = number of minutes
  • cost of company X = 3n+30
  • cost of company Y = 2n+15

To find out how much more company X charges, we subtract the two cost expressions

CompanyX - CompanyY = (3n+30)-(2n+15) = 3n+30-2n-15 = n+15 which is the final answer.

--------------

An example:

Let's say you talk on the phone for n = 20 minutes.

Company X would charge you 3n+30 = 3*20+30 = 90 cents

Company Y would charge you 2n+15 = 2*20+15 = 55 cents

The difference of which is 90-55 = 35 cents.

If you plugged n = 20 into the n+15 expression we got, then n+15 = 20+15 = 35 matches up with the previous 35 cents.

This example helps confirm the answer. I'll let you try out other examples.

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3 years ago
4. The population of Bay Village is 35,000 today. Every year the
frosja888 [35]

Answer:

Linear Model:   y(x)=35,000+750x

Step-by-step explanation:

In principle <em>Linear Models </em>are employed when we want to define a relationship between an independent and a dependent variable. <em>Linear Models</em> are also known as<em> Functions </em>, where one variable is expressed as a function of <em>at least one</em> other variable. The most common example would be a dependent variable y that is directly linked as a response to any changes of an independent variable x. The most common expression of such relationship would be y=ax where a is the relationship factor between y and x and is also known as the <em>slope </em>of the function (representing a rate of change of that function).

In this question we are told that the population of Bay Village today is 35,000. So we know this is our constant variable, lets call it  b.

Next we know that every year the population is increased by 750 people. So we know that our variable and thus our independent variable is every year which we shall call x and our fixed factor is the 750 increment which we will call a.  

From that we can conclude that:

<em>Year 1 Population: 35,000</em>

<em>Year 2 Population: 35,000 + 750 = 35,750</em>

<em>Year 3 Population: 35,750 + 750 = 36,500 </em>

And so on and so forth.<em> </em>

So we want to express the above as a Linear Model of the form:

<em> y = ax + b   </em>Eqn(1).

Thus from Eqn (1) and all information given (i.e. pluging in values) we finally obtain:

y(x)=35,000+750x

Which for every different value of  x (i.e. every year) we can obtain the new and increased population  y(x).

7 0
3 years ago
 A typical tip in a restaurant is​ 15% of the total bill. If the bill is ​$140​, what would the typical tip​ be?
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Typical tip would be $21.00
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Simplest form of 6×/15×
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2/5
I belive that’s the answer
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3 years ago
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