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2 years ago

Two communications companies offer calling plans. With Company X, it costs 30¢ to connect and then

Mathematics

1 answer:

tensa zangetsu [6.8K]2 years ago

8 0

<h3>Answer: n+15</h3>

=======================================================

Explanation:

n = number of minutes
cost of company X = 3n+30
cost of company Y = 2n+15

To find out how much more company X charges, we subtract the two cost expressions

CompanyX - CompanyY = (3n+30)-(2n+15) = 3n+30-2n-15 = n+15 which is the final answer.

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An example:

Let's say you talk on the phone for n = 20 minutes.

Company X would charge you 3n+30 = 3*20+30 = 90 cents

Company Y would charge you 2n+15 = 2*20+15 = 55 cents

The difference of which is 90-55 = 35 cents.

If you plugged n = 20 into the n+15 expression we got, then n+15 = 20+15 = 35 matches up with the previous 35 cents.

This example helps confirm the answer. I'll let you try out other examples.

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Which of the following situations describes a continuous distribution? A probability distribution showing the number of vaccines

lapo4ka [179]

Answer:

Continous distributions:

- A probability distribution showing the average number of days mothers spent in the hospital.

- A probability distribution showing the weights of newborns.

Step-by-step explanation:

A probability distribution showing the number of vaccines given to babies during their first year of life will have a discrete distribution as only a natural number can represent the number of vaccines (0, 1, 2 vaccines and so on).

A probability distribution showing the average number of days mothers spent in the hospital can be described as continous because we are averaging days and this average can be fractional, so it is not discrete.

A probability distribution showing the weights of newborns is continous, as the weights are a continous variable (physical measurement), not discrete.

A probability distribution showing the amount of births in a hospital in a month is a discrete distribution, as the number of births can only be represented by natural numbers.

3 0

4 years ago

Given circle and circle with radii of 6cm and 4cm respectively.

noname [10]

Solution :

Given that :

The radius of circle A = 6 cm

The radius of circle C = 4 cm

In circle A

$\angle EAF = \theta = 140^\circ$

The length of arc EF = $2 \pi r \times \frac{\theta}{360^\circ}$

$=2 \times 3.14 \times 6 \times \frac{140^\circ}{360^\circ}$

= 14.653 cm

In circle C

$\angle GCH = \theta = 140^\circ$

The length of arc GH = $2 \pi r \times \frac{\theta}{360^\circ}$

$=2 \times 3.14 \times 4 \times \frac{140^\circ}{360^\circ}$

= 9.769 cm

Therefore,

The length of EF is 14.653 cm

The length of GH is 9.769 cm

The length of EF is 1.5 times the length of GH

i.e. 14.653 = 1.5 x 9.769

14.653 = 14.653

Hence proved.

6 0

3 years ago

Is it true that any fraction is in its simplest form if and only if the only common factor of the numerator and denominator is 1

fomenos

Answer:

Yes

Step-by-step explanation:

When the greatest common factor of two numbers is 1 or -1, the numbers are known as relatively prime. This means there are no numbers that can be factored out of both of the numbers, meaning if the numerator and denominator are relatively prime, they can not be simplified any further.

8 0

3 years ago

Solve equation by factoring 8x^2-8x=0

dusya [7]

Answer: x= 0 or x= 1

Step by step:

Step 1: Factor left side of equation.

= 8x (x – 1) = 0

Step 2: Set factors equal to 0.

= 8x = 0 , x = -1 = 0

= x = 0 , x = –1

3 0

3 years ago

Plz help. Will give brainliest to best answer

mariarad [96]

Answer:

Step-by-step explanation:

11cos35

6 0

3 years ago

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