a = 11(4b + c) Multiply/distribute 11 into (4b + c) [multiply 11 to 4b and c]
a = 44b + 11c Subtract 44b on both sides
a - 44b = 11c Divide 11 on both sides to get "c" by itself
You can simplify it to this(but Idk if you have to):
Graph the polygon with the given vertices and its image after a reflection in the given line.
1 answer:
The coordinates of the image after reflection over line y = 1 is
preimage Image
J(2, 4 J' (2. -2)
K(-4,-2) K' (-4. 4)
L( − 1, 0) L' (-1, 2)
<h3>How to fine the coordinates of the reflected image</h3>Reflection is one of the movements in transformation that involve creation of mirror image
The reflection to be done is over line y = 1
Transformation rule for reflection over line y at origin (0, 0)) is
(x, y) → (x, -y)
However, reflection over line y = 1 which is (0, 1) is done as follows
J(2, 4) ⇒ (2, 4 - 1) ⇒ (2, 3) ⇒ (2, 1 - 3) → J' (2, -2)
from 4 to 1 = 4 - 1 = 3 units
reflecting 3 units over y = 1
1 - 3 = -2
J' (2, -2)
K(-4,-2) ⇒ (-4, -2 - 1) ⇒ (-4, -3) ⇒ (-4, 1 - -3) ⇒ K' (-4, 4)
from -2 to 1 = -2 - 1 = -3 units
reflecting -3 units over y = 1
1 - -3 = 4
K' (-4, 4)
L (-1, 0) ⇒ (-1, 0 - 1) ⇒ (-1, -1) ⇒ (-1, 1 - - 1) ⇒ L' (-1, 2')
from 0 to 1 = 0 - 1 = -1 unit
reflecting -1 unit over y = 1
1 - -1 = 2
L' (-1, 2)
see graph for more information
Learn more about transformation here:
#SPJ1
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