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3 years ago

On a number line, the distance between x and 8 is 2 units.

Mathematics

1 answer:

vova2212 [387]3 years ago

6 0

Answer:

|8−x|=2

Step-by-step explanation:

because you have to subtract them together to see how far apart they are

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The lunch special at Jimmy John’s costs $5.60. The math club has $50.40 in its treasury. How many lunch specials can the club bu

dolphi86 [110]

Answer:

x=9

Step-by-step explanation:

Equation: 5.60x=50.40

Solve: 5.60x=50.40

Divide both sides by 5.60 ( 5.60x/5.60 ) and ( 50.40/5.60 )

x=9

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3 years ago

5 roses cost $55. What will 4 roses cost?

kodGreya [7K]

Divide 55 by 5. get 11 times that by 4. you're welcome

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3 years ago

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Simplify 30! / 28!<br><br> Please post the correct answer. Don’t send links

viva [34]

The answer is
3 divided by 2
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3 years ago

The perimeter of a triangle is 42 yards. The first side is 5 yards less than the second side, and the third side is 2 yards less

Maru [420]

Let the second side be equal to x Then the first side is x-5 The third side will be x-5-2 = x-7 Therefore you add all the following sides and equate it to 42 yards. Ie x+x+5+x-7 = 42 3x=44 X= 44/3 Therefore the second sides length is 44/3 The first sides length is 44/3 -5 = 29/3 The third side is 44/3 -7 = 23/3

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3 years ago

Lizzie rolls two dice. What is the probability that the sum of the dice is:

zhenek [66]

Answer:

$A.\ \dfrac{1}{3}\\B.\ \dfrac{5}{12}\\C.\ \dfrac{7}{36}\\$

Step-by-step explanation:

Total outcomes possible: 36

A. Divisible by 3

Possible options are:

3, 6, 9 and 12.

Possible outcomes for 3 are: {(1,2), (2,1)} Count 2

Possible outcomes for 6 are: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

Possible outcomes for 9 are: {(3,6), (4,5), (5,4),(6,3)} Count 4

Possible outcomes for 12 are: {(6,6)} Count 1

Total count = 2 + 5 + 4 + 1 = 12

Probability of an event E can be formulated as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

$P(A) = \dfrac{12}{36} = \dfrac{1}{3}$

B. Less than 7:

Possible sum can be 2, 3, 4, 5, 6

Possible cases for sum 2: {(1,1)} Count 1

Possible cases for sum 3: {(1,2), (2,1)} Count 2

Possible cases for sum 4: {(1,3), (3,1), (2,2)} Count 3

Possible cases for sum 5: {(1,4), (2,3), (3,2),(4,1)} Count 4

Possible cases for sum 6: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

Total count = 1 + 2 + 3 + 4 + 5 = 15

$P(B) = \dfrac{15}{36} = \dfrac{5}{12}$

C. Divisible by 3 and less than 7:

$P(A \cap B) = \dfrac{n(A\cap B)}{\text{Total Possible outcomes}}$

Here, common cases are:

Possible outcomes for 3 are: {(1,2), (2,1)} Count 2

Possible outcomes for 6 are: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

$P(A \cap B) = \dfrac{7}{\text{36}}$

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3 years ago