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Otrada [13]
3 years ago
9

Simplify please help

Mathematics
1 answer:
olchik [2.2K]3 years ago
3 0

Answer:

all work is shown/pictured

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Which of the following Triangle cases cannot be solved, using either the law of cosines or law of sines
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The answer is D. You cannot use aaa
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The graph is stretch/shrunk by a factor of a. The Domain is h=
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2 years ago
Please someone help me‼️
Flauer [41]

Answer:

6 m

Step-by-step explanation:

The volume of a cone is found by \frac{\pi r^2h}{3}, so we can plug the values in to get 6pi * r^2 / 3 = 72pi, or 6pi * r^2 = 216 pi, so r^2 = 36 and the radius is 6 m.

4 0
3 years ago
The combined area of a pair of congruent rectangles can be represented, in square units, by the expression 18y^2-818y 2 −8. The
sveta [45]

Answer:

Perimeter = 12y

Step-by-step explanation:

Given

Area = 18y^2 - 8 -- two rectangles

Required

Determine the perimeter of one of the rectangles

First, calculate the area (A) of 1 rectangle

A =\frac{1}{2}Area

A =\frac{1}{2}(18y^2 - 8)

A =9y^2 - 4

Express as difference of two squares

A =(3y - 2)(3y+2)

Area is calculated as:

A = Length * Width

So, by comparison:

Length = 3y - 2

Width = 3y + 2

The perimeter is:

Perimeter = 2 *(Length + Width)

Perimeter = 2 *(3y-2+3y+2)

Collect Like Terms

Perimeter = 2 *(3y+3y-2+2)

Perimeter = 2 *(6y)

Perimeter = 12y

8 0
3 years ago
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