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Romashka-Z-Leto [24]
3 years ago
13

The mean score on a physics test was 75 points. Amy’s score was 67 points, which was 2 standard deviations below the mean.

Mathematics
1 answer:
Marrrta [24]3 years ago
3 0

Answer:

16

Step-by-step explanation:

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Help please #10 if you can
Mice21 [21]

Answer:

200,000 m

Step-by-step explanation:

We will multiply the length of the ant by the number of ants to find out how long the line is.

10 million is 10 with 6 zeros

20 * 10 ^-3   move the decimal 3 places to the left

20. * 10 ^-3  = .02

.02 * 10000000

200000


5 0
3 years ago
Read 2 more answers
Sienna is solving the quadratic equation by completing the square.
pantera1 [17]

Answer:

See below

Step-by-step explanation:

3 (x^2 + 3x) = 4

3 ( x + 3/2)^2   = 4 + 27/4  

4 0
2 years ago
Which series of transformations will not map figure H onto itself
7nadin3 [17]

Answer:

D

Step-by-step explanation:

Given a square with vertices at points (2,1), (1,2), (2,3) and (3,2).

Consider option A.

1st transformation (x+0,y-2) will map vertices of the square into points

  • (2,1)\rightarrow (2,-1);
  • (1,2)\rightarrow (1,0);
  • (2,3)\rightarrow (2,1);
  • (3,2)\rightarrow (3,0).

2nd transformation = reflection over y = 1 has the rule (x,2-y). So,

  • (2,-1)\rightarrow (2,3);
  • (1,0)\rightarrow (1,2);
  • (2,1)\rightarrow (2,1);
  • (3,0)\rightarrow (3,2)

These points are exactly the vertices of the initial square.

Consider option B.

1st transformation (x+2,y-0) will map vertices of the square into points

  • (2,1)\rightarrow (4,1);
  • (1,2)\rightarrow (3,2);
  • (2,3)\rightarrow (4,3);
  • (3,2)\rightarrow (5,2).

2nd transformation = reflection over x = 3 has the rule (6-x,y). So,

  • (4,1)\rightarrow (2,1);
  • (3,2)\rightarrow (3,2);
  • (4,3)\rightarrow (2,3);
  • (5,2)\rightarrow (1,2)

These points are exactly the vertices of the initial square.

Consider option C.

1st transformation (x+3,y+3) will map vertices of the square into points

  • (2,1)\rightarrow (5,4);
  • (1,2)\rightarrow (4,5);
  • (2,3)\rightarrow (5,6);
  • (3,2)\rightarrow (6,5).

2nd transformation = reflection over y = -x + 7 will map vertices into points

  • (5,4)\rightarrow (3,2);
  • (4,5)\rightarrow (2,3);
  • (5,6)\rightarrow (1,2);
  • (6,5)\rightarrow (2,1)

These points are exactly the vertices of the initial square.

Consider option D.

1st transformation (x-3,y-3) will map vertices of the square into points

  • (2,1)\rightarrow (-1,-2);
  • (1,2)\rightarrow (-2,-1);
  • (2,3)\rightarrow (-1,0);
  • (3,2)\rightarrow (0,-1).

2nd transformation = reflection over y = -x + 2 will map vertices into points

  • (-1,-2)\rightarrow (4,3);
  • (-2,-1)\rightarrow (3,4);
  • (-1,0)\rightarrow (2,3);
  • (0,-1)\rightarrow (3,2)

These points are not the vertices of the initial square.

5 0
3 years ago
Max correctly solved this inequality.
Dafna11 [192]

Answer:

B

Step-by-step explanation:

Got it right on edge. mark me brainliest please

6 0
3 years ago
Two consecutive numbers with a sum of 775. What is the value of each of the two numbers?
Mnenie [13.5K]

Answer:

387 and 388

Step-by-step explanation:

775 / 2 = 387.5

387 and 388

3 0
3 years ago
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