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3 years ago

What is40.99 times 2.1

Mathematics

2 answers:

inessss [21]3 years ago

7 0

Answer:

40.99* 2.1= 86.079

Step-by-step explanation:

ANTONII [103]3 years ago

6 0

The anawer is 86.079

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Help me and EXPLAIN plz

dalvyx [7]

Volume=length X breadth X height

hence, volume= 9.6 X 5 X 7 cubic millimeters

which is equal to 336 cubic mm

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3 years ago

You saved $140 on your new laptop because you bought it online. If this was a 20% savings from the original price, Find the orig

Elenna [48]

Let the original cost of laptop=x
Savings=20% = 20/100
Saved amount = $140
Original cost = saved amount * 1/savings
x = 140* 100/20
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3 years ago

3 apples at the store for $3.90. This week he purchased 5 apples for $6.50. WHAT IS THE THE EQUATION IN SLOPE INTERCEPT FORM FOR

qwelly [4]

To find the slope, use y2-y1/x2-x1
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4 0

3 years ago

What is the solution for r in the following system of equations?<br> 2x + 3y = 16<br> 2 + 2y = 10

klio [65]

Answer:

(2,4)

*View attached graph*

Step-by-step explanation:

2x + 3y = 16

2 + 2y = 10

-2 - 2

2y = 8

/2 /2

y = 4

2x + 3y = 16

2x + 3(4) = 16

2x + 12 = 16

- 12 - 12

2x = 4

/2 /2

x = 2

(x,y) -> (2,4)

Hope this helps!

8 0

2 years ago

You work with the office of city planning which is currently evaluating a new contract for a major highway. The chosen contracto

Ipatiy [6.2K]

Answer:

0.5488 = 54.88% probability that there are no defects in the completed highway.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

The portion of highway that your city is building is 30 miles long.

The mean is one defect per 50 miles. Since the highway is 30 miles, we have that:

$\mu = \frac{30}{50} = 0.6$

What is the probability that there are no (0) defects in the completed highway?

This is P(X = 0). So

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-0.6}*0.6^{0}}{(0)!} = 0.5488$

0.5488 = 54.88% probability that there are no defects in the completed highway.

7 0

3 years ago