Answer:
Population of fish in 2010 = 1,646 fish (Approx.)
Step-by-step explanation:
Given:
Population of fish in 2002 = 2100 fish
Decrease rate = 3% per year
Find:
Population of fish in 2010
Computation:
Number of year = 2010 - 2002
Number of year = 8 year
A = P[1+r]ⁿ
Population of fish in 2010 = Population of fish in 2002[1+(-3%)]ⁿ
Population of fish in 2010 = 2100[1-0.03]⁸
Population of fish in 2010 = 2100[0.97]⁸
Population of fish in 2010 = 2100[0.7837]
Population of fish in 2010 = 1645.77
Population of fish in 2010 = 1,646 fish (Approx.)
The equation of y for that expression would be y = (-4x+9)/-5.
Solving this involves basic arithmetic.
The number is -10
Let the number that is a product with 6 be x.
This product is the same as 40 less than twice that same number.
Thus; 6x = 2x - 40
Rearranging, we have;
6x -2x = -40
4x = -40
x = -40/4
x = -10
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Answer:
$53.90
Step-by-step explanation:
30% of $77 = $77 * 30/100 = $77 * 0.3 = $23.10 (discount)
Regular price is $77, discount is $23.10, so the item is now
$77 - $23.10 = $53.90
Shorter way of solving this could be as follows:
The regular price is 100% of the price. If the item is on 30% discount, so it means now it worths 70% (which is 100% - 30%) of the regular price:
$77 * 70/100 = $77 * 0.7 = $53.90