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Andrew [12]
3 years ago
7

Help me please not tryna fail !

Mathematics
2 answers:
sp2606 [1]3 years ago
7 0

Answer:

x=27

∠JLK=2x+1=2(27)+1=55

Step-by-step explanation:

∠A+∠K=180

3x+13+∠K=180

∠K=167-3x

∠K+∠L+∠J=180

167-3x+39+2x+1=180

207-x=180

x=27

∠JLK=2x+1=2(27)+1=55

Don't worry, you aren't gonna fail. Take a deep breath and relax. Geometry is tricky but you got this. Have a nice night.

notka56 [123]3 years ago
3 0

Answer:

  • x = 27°
  • ∠JLK = 55°

Step-by-step explanation:

<u>∠AKL is exterior angle and as per property it is equal to sum of two non-adjacent angles:</u>

  • ∠AKL = ∠ KJL + ∠JLK
  • 3x + 13° = 39° + 2x + 1°

<u>Solving for x</u>

  • 3x - 2x = 39° + 1 - 13
  • x = 27°

<u>And finding the value of ∠JLK:</u>

  • ∠JLK = 2x + 1 = 2*27° + 1° = 55°
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Rasheed bought two kinds of candy bars, chocolate and toffee, that came in packages of 2 bars each. He handed out 2/3 of the cho
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Answer:

9 packages of chocolate bars

Step-by-step explanation:

Let he bought c packages of chocolate bars and t packages of toffee bars,

Since, he bought 1 fewer package of chocolate bars than toffee bars.

⇒ c = t - 1  -----(1)

Also, he handed out out \frac{2}{3} of the chocolate bars and \frac{3}{5} of the toffee bars,

If he handed out the same number of each kind of candy bar.

\implies \frac{2}{3}\times c=\frac{3}{5}\times t

10c = 9t     ( By cross multiplication )

\implies t=\frac{10}{9}c    ( Division property of equality )

From equation (1),

c=\frac{10}{9}c-1

1=\frac{10}{9}c-c

1=\frac{10c-9c}{9}

1=\frac{c}{9}

\implies c = 9

Hence, he bought 9 packages of chocolate bars.

4 0
3 years ago
Evaluate the expression |-16|-|-2|
DIA [1.3K]
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3 years ago
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In a class of students, the following data table summarizes how many students passed a test and complete the homework due the da
Alexxandr [17]

20 / 27 is the probability that a student chosen randomly from the class passed the test or completed the homework.

<u>Step-by-step explanation:</u>

To find the probability that a student chosen randomly from the class passed the test or complete the homework :

Let us take,

  • Event A ⇒ a student chosen randomly from the class passed the test
  • Event B ⇒ a student chosen randomly from the class complete the homework

We need to find out P (A or B) which is given by the formula,

⇒ P (A or B) = P(A) + P(B) - P(A∪B)

<u>From the given table of data,</u>

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P(A) = No.of students passed / Total students in the class

P(A) ⇒ 18 / 27

  • The no.of students completed the homework ⇒ 15+2 = 17 students.

P(B) = No.of students completed the homework / Total students in the class

P(B) ⇒ 17 / 27

  • The no.of students who passes the test and completed the homework = 15 students.

P(A∪B) = No.of students both passes and completes the homework / Total

P(A∪B) ⇒ 15 / 27

Therefore, to find out the P (A or B) :

⇒ P(A) + P(B) - P(A∪B)

⇒ (18 / 27) + (17 / 27) - (15 / 27)

⇒ 20 / 27

∴ The P (A or B) is 20/27.

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3 years ago
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Answer:

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- 999 whole numbers from 1 to 999 (counting from 1, 2, 3, 4...897, 898, 899)

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there are 900 3-digit natural numbers!  

comment or message me if you are still confused!

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