Answer:
the third one
Step-by-step explanation:
it's the only correct one with only addition
D.) Subtracting 9 from each side.
Answer:
x = ±25
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
x² = 625
<u>Step 2: Solve for </u><em><u>x</u></em>
- Square root both sides: x = ±25
<u>Step 3: Check</u>
<em>Plug in x into the original equation to verify it's a solution.</em>
x = -25
- Substitute in <em>x</em>: (-25)² = 625
- Exponents: 625 = 625
Here we see that 625 does indeed equal 625.
∴ x = -25 is a solution to the equation.
x = 25
- Substitute in <em>x</em>: 25² = 625
- Exponents: 625 = 625
Here we see that 625 does indeed equal 625.
∴ x = 25 is a solution to the equation.
The answer is 0
Because if you look at where it says B on the number line and you look below it it says 0
XZ ≅ EG and YZ ≅ FG is enough to make triangles to be congruent by HL. Option b is correct.
Two triangles ΔXYZ and ΔEFG, are given with Y and F are right angles.
Condition to be determined that proves triangles to be congruent by HL.
<h3>What is HL of triangle?</h3>
HL implies the hypotenuse and leg pair of the right-angle triangle.
Here, two right-angle triangles ΔXYZ and ΔEFG are congruent by HL only if their hypotenuse and one leg are equal, i.e. XZ ≅ EG and YZ ≅ FG respectively.
Thus, XZ ≅ EG and YZ ≅ FG are enough to make triangles congruent by HL.
Learn more about HL here:
brainly.com/question/3914939
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In ΔXYZ and ΔEFG, angles Y and F are right angles. Which set of congruence criteria would be enough to establish that the two triangles are congruent by HL?
A.
XZ ≅ EG and ∠X ≅ ∠E
B.
XZ ≅ EG and YZ ≅ FG
C.
XZ ≅ FG and ∠X ≅ ∠E
D.
XY ≅ EF and YZ ≅ FG
