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sergeinik [125]
3 years ago
10

Given the following skeleton equation, what are the coefficients for the chemicals in the reaction? __ FeSO4 + __ Al(OH)3 → __ A

l2(SO4)3 + __ Fe(OH)2
Chemistry
2 answers:
Savatey [412]3 years ago
5 0
3 FeSO4 + 2 Al(OH)3 -> 1 Al2(SO4)3 + 3 Fe(OH)2
Lelechka [254]3 years ago
3 0

Answer:

3 FeSO4 + 2 Al(OH)3 -> 1 Al2(SO4)3 + 3 Fe(OH)2

Explanation:

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Convert 6.35 grams of aluminum sulfate to moles​
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Answer:

There are 0.0186 moles of formula units in 6.35 grams of aluminum sulfate \rm Al_2(SO_4)_3.

Explanation:

What's the empirical formula of aluminum sulfate?

Sulfate is an anion with a charge of -2 per ion. When sulfate ions are bonded to metals, the compound is likely ionic.

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Pairing three \rm {SO_4}^{2-} ions with two \rm Al^{3+} will balance the charge. Hence the empirical formula: \rm Al_2(SO_4)_3.

What's the mass of one mole of aluminum sulfate? In other words, what's the formula mass of \rm Al_2(SO_4)_3?

Refer to a modern periodic table for relative atomic mass data:

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\underbrace{2\times 26.982}_{\rm Al} + \underbrace{3\times 32.06}_{\rm S} + \underbrace{12\times 15.999}_{\rm O} = \rm 342.132\;g\cdot mol^{-1}.

How many moles of formula units in 6.35 grams of \rm Al_2(SO_4)_3?

\displaystyle n = \frac{m}{M} = \rm \frac{6.35\;g}{342.132\;g\cdot mol^{-1}} = 0.0186\;mol.

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