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3 years ago

In a biochemical reaction, an enzyme acts as a catalyst, causing the

1 answer:

5 0

<span>The question says, in biochemical reactions, enzymes acts as catalyst causing the............. The correct option is A. The minimum energy that must be overcome before a chemical reaction occur is activation energy. Enzymes act as catalyst to lower the activation energy so that the biochemical reaction can occur. </span>

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Calculate ΔHo for the following reaction ussing the given bond dissociation energiesCH4(g) + 2O2(g) --> CO2(g) + 2H2O(g)BOND

Mazyrski [523]

Answer:

The ΔH° for the following reaction is -794 kJ, hence exothermic reaction,

Explanation:

$CH_4(g) + 2O_2(g)\rightarrow CO_2(g) + 2H_2O(g) ,$ ΔH° = ?

We are given with:

$\Delta H_{O-O}=142 kJ/mol$

$\Delta H_{O=O}=498 kJ/mol$

$\Delta H_{H-O}=459 kJ/mol$

$\Delta H_{C-H}=411 kJ/mol$

$\Delta H_{C-O}=358 kJ/mol$

$\Delta H_{C=O}=799 kJ/mol$

ΔH° =

(Energies required to break bonds on reactant side) - (Energies released on formation of bonds on product side)

$\Delta H^o=(1 mol\times 4\times \Delta H_{C-H}+2 mol\times 1\times \Delta H_{O=O})-(1 mol\times 2\times \Delta H_{C=O}+2 mol\times 2\times\Delta H_{H-O})$

$\Delta H^o=(1 mol\times 4\times 411 kJ/mol+2 mol\times 1\times 498 kJ/mol)-(1 mol\times 2\times 799 kJ/mol+2 mol\times 2\times 459 kJ/mol)$

$\Delta H^o=-794kJ$

$\Delta H^o>0$ endothermic reaction

$\Delta H^o$ exothermic reaction

The ΔH° for the following reaction is -794 kJ, hence exothermic reaction,

4 0

4 years ago

can anyone help me with this and if my score is perfect i will brainlist u and follow you and please the answer must be the righ

mario62 [17]

Answer:

1.CL

2.SP

3.CL

4.SL

5.SL

6.SP

7.SL

8.CL

9.SL

10.CL

Explanation:

HOPE ITS HELP

5 0

3 years ago

Scientific predictions based on laws are formulated using:

abruzzese [7]

Answer:

A. deductive reasoning

7 0

4 years ago

Read 2 more answers

A mixture of CO2 and Kr weighs 35.0 g and exerts a pressure of 0.708 atm in its container. Since Kr is expensive, you wish to re

ollegr [7]

Explanation:

Since, it is given that carbon dioxide is completely removed by absorption with NaOH. And, pressure inside the container is 0.250 atm.

For Kr = 0.250 atm and pressure $CO_{2}$ will be calculated as follows.

$CO_{2}$ = (0.708 - 0.250) atm

= 0.458 atm

Now, we will calculate the mole fraction as follows.

$CO_{2} = \frac{0.458}{0.708}$

= 0.646

Kr = $\frac{0.250}{0.708}$

= 0.353

Now, we will convert into gram fraction as follows.

$CO_{2} = 0.646 \times 44$

= 28.424

Kr = $0.353 \times 83.78$

= 29.57

Therefore, total mass is calculated as follows.

Total mass = (28.424 + 29.57)

= 57.994

Hence, the percentage of $CO_{2}$ and Kr are calculated as follows.

$CO_{2} = \frac{28.424}{57.99} \times 100$

= 49%

Kr = $\frac{29.57}{57.99} \times 100$

= 51%

Hence, amount of $CO_{2}$ and Kr present i mixture is as follows.

$CO_{2}$ in mixture = $35 \times 0.49$

= 17.15 g

Kr = $35 \times 0.51$

= 17.85 g

Thus, we can conclude that 17.15 g of $CO_{2}$ is originally present and 17.85 g of Kr is recovered.

6 0

3 years ago

23.It is possible to dilute a solution by...Select one:a. adding more solute to the solution.b. adding more solvent to the solut

joja [24]

To dilute a solute in a solution, it is necessary to add a proper solvent for the reaction to occur, and adding more solvent will cause the solution to dilute even more, therefore the best answer will be letter B

7 0

1 year ago