Solve the equation. n + 1.5 = 13.8 n =??? Can somebody also answer this

Broderick deposits $6,000 in an account that earns 5.5% simple interest paid annually. How long will it be before the total amou

emmainna [20.7K]

i=prt
where i is interest (9000-6000 = $3000 interest)
p is principle ($6000)
r is rate (5.5%) [taking that its 5.5%pa]
t is time

substitute these into the equation
3000 = $6000 x 5.5% x t
t = 3000 divided by (6000x5.5%)
= 3000 divided by 330
t=100/11 years
it would take 100/11 years which is approx 9.1 years

6 0

3 years ago

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A 10 ft pole has a support rope that extends from the top of the pole to the ground. The rope and the ground form a 30 degree an

mr Goodwill [35]

Answer:

The length of rope is 20.0 ft . Hence, option (1) is correct.

Step-by-step explanation:

In the figure below AB represents pole having height 10 ft and AC represents the rope that is from the top of pole to the ground. BC represent the ground distance from base of tower to the rope.

The rope and the ground form a 30 degree angle that is the angle between BC and AC is 30°.

In right angled triangle ABC with right angle at B.

Since we have to find the length of rope that is the value of side AC.

Using trigonometric ratios

$\sin C=\frac{\text{perpendicular}}{\text{hypotenuse}}$

$\sin C=\frac{AB}{AC}$

Putting values,

$\sin 30^\circ} =\frac{10}{AC}$

We know, $\sin 30^\circ}=\frac{1}{2}$

$\frac{1}{2} =\frac{10}{AC}$

On solving we get,

AC= 20.0 ft

Thus, the length of rope is 20.0 ft

Hence, option (1) is correct.

8 0

3 years ago

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What is an equation of the line that passes through the points (-6, -2) and

den301095 [7]

Answer:

The equation of line is: $\mathbf{4x-3y=-18}$

Step-by-step explanation:

We need to find an equation of the line that passes through the points (-6, -2) and (-3, 2)?

The equation of line in slope-intercept form is: $y=mx+b$

where m is slope and b is y-intercept.

We need to find slope and y-intercept.

Finding Slope

Slope can be found using formula: $Slope=\frac{y_2-y_1}{x_2-x_1}$

We have $x_1=-6,y_1=-2, x_2=-3, y_2=2$

Putting values and finding slope

$Slope=\frac{2-(-2)}{-3-(-6)}\\Slope=\frac{2+2}{-3+6} \\Slope=\frac{4}{3}$

So, we get slope: $m=\frac{4}{3}$

Finding y-intercept

Using point (-6,-2) and slope $m=\frac{4}{3}$ we can find y-intercept

$y=mx+b\\-2=\frac{4}{3}(-6)+b\\-2=4(-2)+b\\-2=-8+b\\b=-2+8\\b=6$

So, we get y-intercept b= 6

Equation of required line

The equation of required line having slope $m=\frac{4}{3}$ and y-intercept b = 6 is

$y=mx+b\\y=\frac{4}{3}x+6$

Now transforming in fully reduced form:

$y=\frac{4x+6*3}{3} \\y=\frac{4x+18}{3} \\3y=4x+18\\4x-3y=-18$

So, the equation of line is: $\mathbf{4x-3y=-18}$

6 0

2 years ago

A barber cuts 3 people's hair in 35 minutes. Each haircut takes at least 10 minutes, and fhe first haircut takes the most time.

olchik [2.2K]

15 minutes, 10 minutes, 10 minutes? I think so

5 0

3 years ago

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Which phrase best describes the translation from the graph y=(x-5)^2+7 to the graph of y=(x+1)^2-2

Helga [31]

Start from the parent function $f(x)=x^2$

In the first case, you are computing

$f(x-5)+7$

In the second case, you are computing

$f(x+1)-2 /tex] There are two translation going on: when you transform [tex] f(x) \to f(x+k)$ , you translate the function horizontally, $k$ units left if $k>0$ and $k$ units right if $k$ .

On the other hand, when you transform $f(x) \to f(x)+k$ , you translate the function vertically, $k$ units up if $k>0$ and $k$ units down if $k$ .

So, the first function is the "original" parabola $f(x)=x^2$ , translated $5$ units right and $7$ units up. Likewise, the second function is the "original" parabola $f(x)=x^2$ , translated $1$ units left and $2$ units down.

So, the transformation from $(x-5)^2+7$ to $(x+1)^2-2$ is: go $6$ units to the left and $2$ units down

8 0

3 years ago

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