After plotting all the points, the only one that makes sense is (4,3).
Answer:
x=-2
Step-by-step explanation:
14+6x=2
Then u move 14 to the other side since it doesn't have a a variable and 2 doesnt also there both just numbers so 14 moved to the otehr side will be -14 so 6x=2-14
6x=-12
x=-12/6=-2
Answer:
The probability that the restaurant can accommodate all the customers who do show up is 0.3564.
Step-by-step explanation:
The information provided are:
- At 7:00 pm the restaurant can seat 50 parties, but takes reservations for 53.
- If the probability of a party not showing up is 0.04.
- Assuming independence.
Let <em>X</em> denote the number of parties that showed up.
The random variable X follows a Binomial distribution with parameters <em>n</em> = 53 and <em>p</em> = 0.96.
As there are only 50 sets available, the restaurant can accommodate all the customers who do show up if and only if 50 or less customers showed up.
Compute the probability that the restaurant can accommodate all the customers who do show up as follows:
![P(X\leq 50)=1-P(X>50)\\=1-P(X=51)-P(X=52)-P(X=53)\\=1-[{53\choose 51}(0.96)^{51}(0.04)^{53-51}]-[{53\choose 52}(0.96)^{52}(0.04)^{53-52}]\\-[{53\choose 53}(0.96)^{53}(0.04)^{53-53}]\\=1-0.27492-0.25377-0.11491\\=0.3564](https://tex.z-dn.net/?f=P%28X%5Cleq%2050%29%3D1-P%28X%3E50%29%5C%5C%3D1-P%28X%3D51%29-P%28X%3D52%29-P%28X%3D53%29%5C%5C%3D1-%5B%7B53%5Cchoose%2051%7D%280.96%29%5E%7B51%7D%280.04%29%5E%7B53-51%7D%5D-%5B%7B53%5Cchoose%2052%7D%280.96%29%5E%7B52%7D%280.04%29%5E%7B53-52%7D%5D%5C%5C-%5B%7B53%5Cchoose%2053%7D%280.96%29%5E%7B53%7D%280.04%29%5E%7B53-53%7D%5D%5C%5C%3D1-0.27492-0.25377-0.11491%5C%5C%3D0.3564)
Thus, the probability that the restaurant can accommodate all the customers who do show up is 0.3564.